### Problem Statement:Determine the magnitude of the resultant force acting on the corbel and its direction \( \theta \) measured counterclockwise from the x-axis.### Explanation of Diagram:The diagram above illustrates three forces acting at a point, represented as follows:- \( F_1 = 700 \) lb: This force is applied at an angle of 30 degrees above the positive x-axis.- \( F_2 = 400 \) lb: This force is applied vertically upward along the y-axis.- \( F_3 = 600 \) lb: This force is applied in the third quadrant. The direction forms a right triangle with sides 3, 4, and 5, indicating it makes an angle with the x-axis. The exact angle is not specified but can be calculated using the arctangent function or by recognizing the 3-4-5 triangle's properties.### Steps to Solve:1. **Resolve Each Force into Components:** - \( F_1 \) has both x and y components. - \( F_2 \) is along the y-axis. - \( F_3 \) should be broken into x and y components using the 3-4-5 rule.2. **Sum the X and Y Components Separately:** - \( \Sigma F_x = F_{1x} + F_{2x} + F_{3x} \) - \( \Sigma F_y = F_{1y} + F_{2y} + F_{3y} \)3. **Calculate the Magnitude of the Resultant Force:** - \( F_R = \sqrt{(\Sigma F_x)^2 + (\Sigma F_y)^2} \)4. **Determine the Direction \( \theta \):** - \( \theta = \tan^{-1}\left(\frac{\Sigma F_y}{\Sigma F_x}\right) \)### Example Calculation:1. Resolve \( F_1 \) into components: - \( F_{1x} = 700 \, \text{lb} \cdot \cos(30^\circ) = 700 \, \text{lb} \cdot \approx 0.866 \approx 606.2 \, \text{lb} \) - \( F_{1y} = 700 \, \text{lb} \cdot \

break force into components to get the resultant.

Answered: F2=400L6 F3=60016 Fi=70olb 30°…

F2=400L6 F3=60016 Fi=70olb 30° Detremine the magnitude of the resultant force acting on the corbel and its direction 0 measured counterclockwise from the x axis.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: 1.2.4

A: Weight acts at the mid pointIf you have any doubt please comment

Q: Determine the magnitude and direction θ of theresultant force FR. Express the result in terms of…

A: Consider the following figure: Completing the parallelogram

Q: Q6 Draw the influence line for the force in (a) member JI, (b) member IE, and (c) member EF. L K 1 H…

A: Given data:

Q: 5. DETERMINE THE MOMENT OF THE FORCE ABOUT POINT O IF F IS 550N. 0.4 m FIGURE 5 0.3 m F 300

A: Resolve force in horizontal and vertical direction. Moment (M) = r*F Where,…

Q: The two structural members, one of which is in tension and the other in compression, exert the…

Q: a. Calculate reactive forces. b. Plot Shear & Moment Diagrams labeled with pertinent values. c.…

A: As per Bartleby's guidelines we are supposed to answer only first three questions. Kindly repost…

Q: X Answer: 12.3 × (-35.6) F4 d F3 = 90° Y Y F₁ A B F2 X Find the moment about O of the resultant of…

A: Given -F1=34 lbF2=42.7 lbF3=12 lbF4= 45.1 lb A= 59.9°B=43.3° d= 3ft

Q: B α P A 22 in. -8 in. Fig. P3.6, P3.7, and P3.8

A: As per bartleby guidelines. We have to solve 1st question in case of multiple question. Please…

Q: Link AB rotates through a limited range of the angle ẞ, and its end A causes the slotted link AC to…

A: First, we need to convert the given angle B from degrees to radians. We know that 1 radian is…

Q: 1. If the shear at a point 1m from the roller support is equal to -217.65765765766kN, determine the…

A: Moment Area Method: The region under the curvature diagram between two points is adequate to the…

Concept explainers

Mechanics of Solids

It is the study of the behavior of solid materials, their characteristics under various circumstances such as variation in external forces, temperature, and other internal factors. It is one of most important study in the field of engineering science, especially chemistry and mechanical engineering. In rigid body, the idealization of the solid body in which deformation is neglected. Deformation is known as the force acting on the solid state system which exerts change in its shape of the body but it continues to be at rest or in a uniform motion but it cannot accelerate. But those solid systems do have elasticity, compressibility and can be bent. This field is very vast since there are wide range of materials around us.

Question

100%

### Problem Statement:

Determine the magnitude of the resultant force acting on the corbel and its direction \( \theta \) measured counterclockwise from the x-axis.

### Explanation of Diagram:

The diagram above illustrates three forces acting at a point, represented as follows:

- \( F_1 = 700 \) lb: This force is applied at an angle of 30 degrees above the positive x-axis.
- \( F_2 = 400 \) lb: This force is applied vertically upward along the y-axis.
- \( F_3 = 600 \) lb: This force is applied in the third quadrant. The direction forms a right triangle with sides 3, 4, and 5, indicating it makes an angle with the x-axis. The exact angle is not specified but can be calculated using the arctangent function or by recognizing the 3-4-5 triangle's properties.

### Steps to Solve:

1. **Resolve Each Force into Components:**
- \( F_1 \) has both x and y components.
- \( F_2 \) is along the y-axis.
- \( F_3 \) should be broken into x and y components using the 3-4-5 rule.

2. **Sum the X and Y Components Separately:**
- \( \Sigma F_x = F_{1x} + F_{2x} + F_{3x} \)
- \( \Sigma F_y = F_{1y} + F_{2y} + F_{3y} \)

3. **Calculate the Magnitude of the Resultant Force:**
- \( F_R = \sqrt{(\Sigma F_x)^2 + (\Sigma F_y)^2} \)

4. **Determine the Direction \( \theta \):**
- \( \theta = \tan^{-1}\left(\frac{\Sigma F_y}{\Sigma F_x}\right) \)

### Example Calculation:

1. Resolve \( F_1 \) into components:
- \( F_{1x} = 700 \, \text{lb} \cdot \cos(30^\circ) = 700 \, \text{lb} \cdot \approx 0.866 \approx 606.2 \, \text{lb} \)
- \( F_{1y} = 700 \, \text{lb} \cdot \

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Step by step

Solved in 3 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Dynamics
The tank truck is filled to its top with water. Determine the magnitude of the resultant force on the elliptical back plate of the tank, and the location of the center of pressure measured from the top of the tank.
Force P with 5.05 kN magnitude acts along the parallelepipeds diagonal CE, pointing towards E 290 mm 290 mm 145 mm Determine the magnitude of the moment of Pabout the following Ines in N-m. (a) Ine OA N-m (b) ine O8 N- m (c) Ine AB N-m (d) Ine BF N-m (e) ine BG N-m (r) Ine DG N-m (a) Ine 0D N-m (h) Ine OC N-m (1) ine EF N-m (1) Ine OF
The belt passing over the pulley is subjected toforces F1 and F2, each having a magnitude of 40 N. F1 acts inthe -k direction. Replace these forces by an equivalent forceand couple moment at point A. Express the result in Cartesianvector form. Set θ = 0° so that F2 acts in the -j direction.
Two forces F1 and F2 act on the screw eye. If theirlines of action are at an angle θ apart and the magnitude ofeach force is F1 = F2 = F, determine the magnitude of theresultant force FR and the angle between FR and F1.
150 mm 100 mg 200 mm PROBLEM 3.54 A single force P acts at C in a direction perpendicular to the handle BC of the crank shown. Determine the moment M, of P about the x-axis when 8 = 65°, knowing that M, = -15 N - m and M₂ = -36 N - m. Mx = 23.0 N-m
A beam is subjected to force as shown in the figure below. Try to analyze the reaction force of the beam at point A and point C. Assuming that the EI of the entire beam section is constant, try to draw the shear curve and bending moment diagram of the beam. (Moment Curve).
2. Determine the magnitude and direction of the moment of the 50-N force about point O. 50 N Kon 60° 100 mm 45° 200 mm 100 mm-
P = 36 kips 9' B de 2) Assuming that no load acts, compute the reactions and draw the shear and moment curves for the beam in the figure above, if support A settles 0.5" and support C settles 0.75". Assume E = 29,000 ksi and I = 150 in. Label all critical points on the diagrams. Draw the deflected shape also. 6'
The force F = 254 N acts from D towards E, as shown. 165 mm 330 mm 132 mm Determine the magnitudes of the moments of force F in N- m about the following lines. (a) OA N.m (b) ос N. m (c) CG N.m (d) GE N- m (e) GB N-m (f) AF N. m (g) GF N- m