F2 F4 Consider the following values: - F5 a = 7 m; b = 3 m; c = 7 m; d = 3 m; FI = 3 kN; F2 = 11 kN; F3 = 2 kN; F4 = 20 kN; F5 = 2 kN; a = 30°, e= 60° B= 30° 3] What is the resultant moment of the five forces acting on the rod about point C? a) 38.7 AN.m b) 21.1 kNm 07146 KN.m d) 69.1 kN.m ) 51.4 KNm 0 85.3 KN.m

F2 F4 Consider the following values: - F5 a = 7 m; b = 3 m; c = 7 m; d = 3 m; FI = 3 kN; F2 = 11 kN; F3 = 2 kN; F4 = 20 kN; F5 = 2 kN; a = 30°, e= 60° B= 30° 3] What is the resultant moment of the five forces acting on the rod about point C? a) 38.7 AN.m b) 21.1 kNm 07146 KN.m d) 69.1 kN.m ) 51.4 KNm 0 85.3 KN.m

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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F1 = 5 kN F2 = 13 kN 0- 45° B - 30° F3 = 4 kN A B 2 m 7 m F4 = 22 kN a = 30° F5 = 4 kN 1] What is the resultant moment of the five forces acting on the rod about point B? 21 What is the resultant moment of the five forces acting on the rod about point E? 3] What is the moment of the force F1 about point D? 41 What is the moment of the force F2 about point E? 5] What is the moment of the force F5 about point B?
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ENGINEERING MECHANICS
F = (-6i + 4j+ 8k) kN PROBLEM 9 4 m Determine the moment of the force about Point P 0. Express the result as a Cartesian vector. 3 m 6 m 1 m A) 69.0 kN-m - B) 60 kN-m 2 m- * C) (-40i - 44j - 8k) kN-m • D) (40i + 44j + 8k} kN-m * E) (8i - 28j + 16k) kN-m Answer: C) (-40i - 44j - 8k) kN-m 25/38 250 PM O 55°F AOG A d* 12/13/202 P Type here to search hp ト Insert prt sc 144 esc & * backspace L. 8 Q こk A Instry
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What is the resultant moment of the five forces acting on the rod about point D?
a) What are the tensions in each of the 4 cables supporting the lamp, if the lamp weighs 40 Ibs and the coordinate direction angles for Cable B are a = 95°, ß = 140° and y = 50.44°? Cable B Cable A 30 50 Cable C 3 ft Cable D b) Using the figure above, determine the maximum weight of the lamp if no cable can support more than 75 Ibs of tension? You can reuse the Cartesian force vector expressions for TA, TB And TC From part a. you do not need to derive them again for this part.
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