F1 V+ R 1 1000 B=20 Vsal R_2 700 V. Pnom = 20W ICmax(nom) = 1.5 A VCE (máx) = 80V Timax = 15,0°C
F1 V+ R 1 1000 B=20 Vsal R_2 700 V. Pnom = 20W ICmax(nom) = 1.5 A VCE (máx) = 80V Timax = 15,0°C
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
Question
The characteristics of the transistor in figure F1 are:
Pnom= 20W
Icmax(nom) =1.5 A
VCE(max)=80V
Tjmax = 150 degrees celcius
to. Calculate Vcc(max) to operate at 45 C with a heat sink: 0e-s =2℃/W and 0s-a = 6℃/W
b. Value of R_1 and R_2 for the previous operating point.
c. It is desired that it can dissipate up to 60% of its Pnom, calculate the new heatsink 8s-a
d. Draw on the same plane: the power curve, the DC load line and indicate, in both cases, the
transistor operating point and the corresponding working power.
![F1
V+
R 1
1000
B=20
Vsal
R_2
700
V.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fec6f8144-e87c-4bf8-b3af-878d3d7bc9b4%2F4c7bc1ee-eced-4a0d-9c79-5dafbe4129f7%2F7y6vqat_processed.png&w=3840&q=75)
Transcribed Image Text:F1
V+
R 1
1000
B=20
Vsal
R_2
700
V.
![Pnom
=
20W
ICmax(nom)
= 1.5 A
VCE (máx)
=
80V
Timax
=
15,0°C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fec6f8144-e87c-4bf8-b3af-878d3d7bc9b4%2F4c7bc1ee-eced-4a0d-9c79-5dafbe4129f7%2Fh84dun5_processed.png&w=3840&q=75)
Transcribed Image Text:Pnom
=
20W
ICmax(nom)
= 1.5 A
VCE (máx)
=
80V
Timax
=
15,0°C
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