F1 = 5 kNF2 = 13 kN0- 45°B- 30°F3 = 4 kNA2 m2.7 mF4 = 22 kNE l a= 30°F5 = 4 kNsting on the rod about point B?kN.m2] What is the resultant moment of the five forces acting on the rod about point E?5 m

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F1 = 5 kN F2 = 13 kN e- 45° B - 30° F3 = 4 kN A 2 m F4 = 22 kN D El a = 30° F5 = 4 kN on the rod about point B2 kN.m 2] What is the resultant moment of the five forces acting on the rod about point E?

F1 = 5 kN F2 = 13 kN e- 45° B - 30° F3 = 4 kN A 2 m F4 = 22 kN D El a = 30° F5 = 4 kN on the rod about point B2 kN.m 2] What is the resultant moment of the five forces acting on the rod about point E?

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Concept explainers

Basic Terminology in Mechanics

The area of science and mathematics concerned the motion of the objects, the relation between the force matter, and motion if specified. Forces exerted over the objects result in displacements or changes in the position of an object concerning its environment. This branch of physics keeps its roots in Ancient Greece in the form of the scripts of Aristotle and Archimedes.

Question

F1 = 5 kN
F2 = 13 kN
0- 45°
B- 30°
F3 = 4 kN
A
2 m
2.
7 m
F4 = 22 kN
E l a= 30°
F5 = 4 kN
sting on the rod about point B?
kN.m
2] What is the resultant moment of the five forces acting on the rod about point E?
5 m

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