(F). (Round to three decimal places as Evaluate the formula E=z, # where z = 1.960, o= 32.43, and n = 45. *** needed.)

MATLAB: An Introduction with Applications
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Q5 

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**Evaluating the Margin of Error in Statistical Analysis**

In statistics, the margin of error (E) is a measure of the expected variability of a sample estimate from the true population parameter. It is calculated using the formula:

\[ E = z \times \left( \frac{\sigma}{\sqrt{n}} \right) \]

Where:
- \( z \) is the z-score corresponding to the desired confidence level.
- \( \sigma \) (sigma) is the standard deviation of the population.
- \( n \) is the sample size.

Given the following values:
\[ z = 1.960, \sigma = 32.43, \text{ and } n = 45 \]

We can substitute these values into the formula to find the margin of error.

Substitute the values into the formula:
\[ E = 1.960 \times \left( \frac{32.43}{\sqrt{45}} \right) \]

1. Calculate the square root of the sample size (n):
\[ \sqrt{45} \approx 6.708 \]

2. Divide the standard deviation (\(\sigma\)) by the square root of the sample size (\( \sqrt{n} \)):
\[ \frac{32.43}{6.708} \approx 4.835 \]

3. Multiply the result by the z-score:
\[ E = 1.960 \times 4.835 \approx 9.470 \]

Therefore, the margin of error \( E \) is:
\[ E \approx 9.470 \]

(Rounded to three decimal places as needed.)

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Transcribed Image Text:--- **Evaluating the Margin of Error in Statistical Analysis** In statistics, the margin of error (E) is a measure of the expected variability of a sample estimate from the true population parameter. It is calculated using the formula: \[ E = z \times \left( \frac{\sigma}{\sqrt{n}} \right) \] Where: - \( z \) is the z-score corresponding to the desired confidence level. - \( \sigma \) (sigma) is the standard deviation of the population. - \( n \) is the sample size. Given the following values: \[ z = 1.960, \sigma = 32.43, \text{ and } n = 45 \] We can substitute these values into the formula to find the margin of error. Substitute the values into the formula: \[ E = 1.960 \times \left( \frac{32.43}{\sqrt{45}} \right) \] 1. Calculate the square root of the sample size (n): \[ \sqrt{45} \approx 6.708 \] 2. Divide the standard deviation (\(\sigma\)) by the square root of the sample size (\( \sqrt{n} \)): \[ \frac{32.43}{6.708} \approx 4.835 \] 3. Multiply the result by the z-score: \[ E = 1.960 \times 4.835 \approx 9.470 \] Therefore, the margin of error \( E \) is: \[ E \approx 9.470 \] (Rounded to three decimal places as needed.) ---
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