F. `N' `N' HN, Amoxicillin NH2 H H CH3 CH3 HO CO2H Identify the functional groups present in each drug and predict the drug solubility based on the given table. (See attached examples)

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Identify the functional groups and predict the solubility of Ciprofloxacin and amoxicillin. Provide drawing and explanation. Table on solubility is given and an example. Thank you
Ciprofloxacin
F.
`OH
HN,
Amoxicillin
NH2 H
„CH3
CH3
НО
CO,H
Identify the functional groups present in each
drug and predict the drug solubility based on the
given table. (See attached examples)
Transcribed Image Text:Ciprofloxacin F. `OH HN, Amoxicillin NH2 H „CH3 CH3 НО CO,H Identify the functional groups present in each drug and predict the drug solubility based on the given table. (See attached examples)
Table (base here)
pi Value
Fragment
C (aliphatic/cyclic)
+0.5
C (alkene-aliphatic/cyclic)
+0.33
(phenyl/benzene ring) C,H;-
+2.0
>/= to +0.5
water insoluble
Halogens (CI, F, Br)
+0.5
0,NO
+0.2
Intramolecular hydrogen bonding (IMHB)
+0.65
< +0.5
+0.5
water soluble
(carboxylic acid) 0=c-o
-0.7
(amide) 0=C-N
-0.7
O(hydroxyl, phenol, ether)
-1.0
N (amine-aliphatic/cyclic/aromatic)
-1.0
0,N (aliphatic)
-0.85
0,N (aromatic)
-0.28
example
Total: 5.28
Carbon
aliphatice
WATER INSOLUBLE
H,CO
Carbon
aliphatic=
0.5
Cyclic
alkene=0.33
H,CO
Carbon
alphatic=
OCH3 05
OCN=-0.7
Carbon
OCH3 aliphatic=
H.
Carbon
cyclic= 0.5
0.5
H,C
Benzene=2
Carbon
aliphatice
IMHB= 0.65
0.5
I ZI
Transcribed Image Text:Table (base here) pi Value Fragment C (aliphatic/cyclic) +0.5 C (alkene-aliphatic/cyclic) +0.33 (phenyl/benzene ring) C,H;- +2.0 >/= to +0.5 water insoluble Halogens (CI, F, Br) +0.5 0,NO +0.2 Intramolecular hydrogen bonding (IMHB) +0.65 < +0.5 +0.5 water soluble (carboxylic acid) 0=c-o -0.7 (amide) 0=C-N -0.7 O(hydroxyl, phenol, ether) -1.0 N (amine-aliphatic/cyclic/aromatic) -1.0 0,N (aliphatic) -0.85 0,N (aromatic) -0.28 example Total: 5.28 Carbon aliphatice WATER INSOLUBLE H,CO Carbon aliphatic= 0.5 Cyclic alkene=0.33 H,CO Carbon alphatic= OCH3 05 OCN=-0.7 Carbon OCH3 aliphatic= H. Carbon cyclic= 0.5 0.5 H,C Benzene=2 Carbon aliphatice IMHB= 0.65 0.5 I ZI
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