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(f) X²0.995, 25

(f) X²0.995, 25

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Transcription for Educational Website: --- **Title: Determining Chi-Square Values** Determine the values of the following quantities. (Round your answers to two decimal places.) **Use SALT** 1. \( \chi^2_{0.05, 5} \) - Result: 11.07 ✓ 2. \( \chi^2_{0.05, 25} \) - Result: 37.65 ✓ 3. \( \chi^2_{0.01, 25} \) - Result: 44.31 ✓ 4. \( \chi^2_{0.005, 25} \) - Result: 46.93 ✓ 5. \( \chi^2_{0.95, 25} \) - Result: 14.61 ✓ 6. \( \chi^2_{0.995, 25} \) - Status: Incorrect ✕ **Explanation:** Each expression represents a chi-square value with specific degrees of freedom and significance levels. The respective results are calculated values for these expressions, with check marks for correct responses and an "X" for an incorrect one. This exercise helps in understanding the usage of chi-square distributions in statistical analysis. ---
Transcribed Image Text:Transcription for Educational Website: --- **Title: Determining Chi-Square Values** Determine the values of the following quantities. (Round your answers to two decimal places.) **Use SALT** 1. \( \chi^2_{0.05, 5} \) - Result: 11.07 ✓ 2. \( \chi^2_{0.05, 25} \) - Result: 37.65 ✓ 3. \( \chi^2_{0.01, 25} \) - Result: 44.31 ✓ 4. \( \chi^2_{0.005, 25} \) - Result: 46.93 ✓ 5. \( \chi^2_{0.95, 25} \) - Result: 14.61 ✓ 6. \( \chi^2_{0.995, 25} \) - Status: Incorrect ✕ **Explanation:** Each expression represents a chi-square value with specific degrees of freedom and significance levels. The respective results are calculated values for these expressions, with check marks for correct responses and an "X" for an incorrect one. This exercise helps in understanding the usage of chi-square distributions in statistical analysis. ---
An article gives the following observations on maximum concrete pressure (kN/m²): 32.9, 33.8, 41.7, 39.4, 39.8, 35.5, 39.5, 35.8, 35.3, 40.2, 35.3, 41.9 (a) Is it plausible that this sample was selected from a normal population distribution? - Using a normal probability plot, we ascertain that it is **not** plausible that this sample was taken from a normal population distribution. - Using a normal probability plot, we ascertain that it **is** plausible that this sample was taken from a normal population distribution. - Because of the number of observations, we ascertain that it is plausible that this sample was taken from a normal population distribution. - Because of the number of observations, we ascertain that it is **not** plausible that this sample was taken from a normal population distribution. (b) Calculate an upper confidence bound with confidence level 95% for the population standard deviation of maximum pressure. (Round your answer to three decimal places.)
Transcribed Image Text:An article gives the following observations on maximum concrete pressure (kN/m²): 32.9, 33.8, 41.7, 39.4, 39.8, 35.5, 39.5, 35.8, 35.3, 40.2, 35.3, 41.9 (a) Is it plausible that this sample was selected from a normal population distribution? - Using a normal probability plot, we ascertain that it is **not** plausible that this sample was taken from a normal population distribution. - Using a normal probability plot, we ascertain that it **is** plausible that this sample was taken from a normal population distribution. - Because of the number of observations, we ascertain that it is plausible that this sample was taken from a normal population distribution. - Because of the number of observations, we ascertain that it is **not** plausible that this sample was taken from a normal population distribution. (b) Calculate an upper confidence bound with confidence level 95% for the population standard deviation of maximum pressure. (Round your answer to three decimal places.)
Expert Solution
Step 1: We have given that

χ0.995,252

25 is degree of freedom


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