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[f (x)) a d. d f [g (x)] (2)] da dx f(x) 9(x) -1 d da dr da (f (x) + g (x)) ()) + 4 g (2) dr da da lef (x)) = c[f (2) da

[f (x)) a d. d f [g (x)] (2)] da dx f(x) 9(x) -1 d da dr da (f (x) + g (x)) ()) + 4 g (2) dr da da lef (x)) = c[f (2) da

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Which is not a derivative rule?
[f (x)] d d. f l9 (2)) = f ()) 9 (æ)] da dx f(x) + [g (x)] f (z)] -1 d da d dr 9(x) * (f (x) + 9 (2)) – ©)+ (2)| dz da da 글 cf (2)] = cf 1/ (2)] da
Transcribed Image Text:[f (x)] d d. f l9 (2)) = f ()) 9 (æ)] da dx f(x) + [g (x)] f (z)] -1 d da d dr 9(x) * (f (x) + 9 (2)) – ©)+ (2)| dz da da 글 cf (2)] = cf 1/ (2)] da
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