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ƒ (x) = 3.06 – (1−x)(3+x) ½ = 0.1 1 x (1+x) ½/2

ƒ (x) = 3.06 – (1−x)(3+x) ½ = 0.1 1 x (1+x) ½/2

College Algebra
College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter5: Polynomial And Rational Functions
Section: Chapter Questions
Problem 27PT: Find the unknown value. 27. y varies jointly with x and the cube root of 2. If when x=2 and...
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Find the first derivative of the given f(x)

ƒ (x) = 3.06 – (1−x)(3+x) ½ = 0.1 1 x (1+x) ½/2
Transcribed Image Text:ƒ (x) = 3.06 – (1−x)(3+x) ½ = 0.1 1 x (1+x) ½/2
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