f we need to find the equation of a plane when given a point in 3-dimensions and two planes that intersect in a line that is contained in the objective plane, how do we find the line of intersection of the two given planes and then proceed to find two points on that line so that we may find the equation of the objective plane with three points and the cross product (to find the normal plane)? Please do an example with point (3, 1, 4) and planes x + 2y + 3z = 1 and 2x - y + z = -3, and please explain all of the steps and use typefont. Thank you!
f we need to find the equation of a plane when given a point in 3-dimensions and two planes that intersect in a line that is contained in the objective plane, how do we find the line of intersection of the two given planes and then proceed to find two points on that line so that we may find the equation of the objective plane with three points and the cross product (to find the normal plane)? Please do an example with point (3, 1, 4) and planes x + 2y + 3z = 1 and 2x - y + z = -3, and please explain all of the steps and use typefont. Thank you!
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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If we need to find the equation of a plane when given a point in 3-dimensions and two planes that intersect in a line that is contained in the objective plane, how do we find the line of intersection of the two given planes and then proceed to find two points on that line so that we may find the equation of the objective plane with three points and the cross product (to find the normal plane)? Please do an example with point (3, 1, 4) and planes x + 2y + 3z = 1 and 2x - y + z = -3, and please explain all of the steps and use typefont. Thank you!
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