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(F) VS 9. The intersection point of the plane 4x - 2y +z=1 and the line F(t)-2+ (1+t)9 is (A) (-1.-2,1) (1.0) (B) (1.글.-6) (C) (D) (1.5.0) (E) (0..2) (F) (1,1,0) 45° with the

(F) VS 9. The intersection point of the plane 4x - 2y +z=1 and the line F(t)-2+ (1+t)9 is (A) (-1.-2,1) (1.0) (B) (1.글.-6) (C) (D) (1.5.0) (E) (0..2) (F) (1,1,0) 45° with the

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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siiirr please solve question 9

6. At point P(-10,0) in cartesian coordinates, given A = 3P-20 and B = @ + 32. The result of A B (A) 6. (9 9. (B) -6 (E) (D) -9 (F) -3 7. Given the vector field A = 3rt- 2sineê. At point P(1,30°, 0º), the vector perpendicular to A and tangential to the cone 0 = 30° is (A) 3f +30 30 (B) 3P-30 (E) 28 + 30 (D) 3P (F) No answer is correct 8. The distance between the two lines , (t)= + tỷ, F(s)= -2£ + s2 Is (A) V3 (B) 4 () 23 (D) 2. (E) 3 (F) 9. The intersection point of the plane 4x -2y +z = 1 and the line F(t)= & + (1+t)9 is 3 (B) (1,5.0) (A) (-1,-2,1) (D) (1.5.0) (1.-6) (E) (0..2) (C) (1,1,0) (F) of the surface 0 = 45° with the sw
Transcribed Image Text:6. At point P(-10,0) in cartesian coordinates, given A = 3P-20 and B = @ + 32. The result of A B (A) 6. (9 9. (B) -6 (E) (D) -9 (F) -3 7. Given the vector field A = 3rt- 2sineê. At point P(1,30°, 0º), the vector perpendicular to A and tangential to the cone 0 = 30° is (A) 3f +30 30 (B) 3P-30 (E) 28 + 30 (D) 3P (F) No answer is correct 8. The distance between the two lines , (t)= + tỷ, F(s)= -2£ + s2 Is (A) V3 (B) 4 () 23 (D) 2. (E) 3 (F) 9. The intersection point of the plane 4x -2y +z = 1 and the line F(t)= & + (1+t)9 is 3 (B) (1,5.0) (A) (-1,-2,1) (D) (1.5.0) (1.-6) (E) (0..2) (C) (1,1,0) (F) of the surface 0 = 45° with the sw
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