F {u (x, 0)} = F {e*} So, the above equation is expressed as, U (a, 0) = /ñe¯.

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Chapter2: Second-order Linear Odes
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I don't understand why u(a,0)=sqrt(pi)*e^a^2/4. Can you please explain it to me.

6:55 PM Fri May 14
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Math / Bundle: Differential Equations with Bo... / In Problems 1-21 and 24-26 use the Fourier integral transforms of this sec...
: In Problems 1-21 and 24-26 use the Fourier integral transforms of this section to solv...
-ka U (a, t) =
dU
dt
Therefore, the equation is,
dU
+ ka? U (a, t) = 0
dt
The particular solution of the above equation,
U (a, t) = ce¬ka²i.
(2)
At the given boundary condition and use the given identity,
F {u (x, 0)} = F {ex*}
So, the above equation is expressed as,
U (α, 0)
Vñe .
(3)
Substitute t =
O in equation (2),
U α, 0)
(4)
= C.
Equate the equations (3) and (4),
c = Vãe?
|
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Transcribed Image Text:6:55 PM Fri May 14 * 14% 0 AA A bartleby.com G Graded y! Yahoo 1-21 and 24... Sfo Calculator •... Calculus II -... ntitled = bartleby Q Search for textbooks, step-by-step explanatio... Ask an Expert Math / Bundle: Differential Equations with Bo... / In Problems 1-21 and 24-26 use the Fourier integral transforms of this sec... : In Problems 1-21 and 24-26 use the Fourier integral transforms of this section to solv... -ka U (a, t) = dU dt Therefore, the equation is, dU + ka? U (a, t) = 0 dt The particular solution of the above equation, U (a, t) = ce¬ka²i. (2) At the given boundary condition and use the given identity, F {u (x, 0)} = F {ex*} So, the above equation is expressed as, U (α, 0) Vñe . (3) Substitute t = O in equation (2), U α, 0) (4) = C. Equate the equations (3) and (4), c = Vãe? | Thank R4prt9xhe 2 4 7 8. W e r t y u i p %23 & return a S f g j k | ? V m .?123 .?123 LO N :)
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