f= PN 60 where f-frequency in hertz P= number of pairs of poles N= revolution per minute

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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  What is the frequency in hertz (Hz) of the current furnished by an alternator having 8 poles and running at a speed of 750 revolutions per minute?

f=
PN
60
where f-frequency in hertz
P= number of pairs of poles
N= revolution per minute
Transcribed Image Text:f= PN 60 where f-frequency in hertz P= number of pairs of poles N= revolution per minute
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