F, F, -2 m -2 m -2 m E 1.5 m Fg F G H 1.5 m B FA 1.5 m A
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
What is the force in member ED, EH, and EG if
F1 = 29 lbs, F2 = 35 lbs, F3 = 23 lbs. F4 = 63 lbs.
State whether each member is in Tension (T) or
Compression (C).

Transcribed Image Text:### Structural Truss Diagram with Applied Forces
#### Overview
This diagram illustrates a structural truss with several joints and applied forces, labeled as \( F_1, F_2, F_3, \) and \( F_4 \). The truss consists of a series of interconnected beams, forming a supportive framework often used in construction and engineering.
#### Description and Measurements
- **Joints and Points:**
- The truss connects at various points labeled as \( A, B, C, D, E, F, G, H, \) and \( I \).
- Joints \( F \) and \( A \) are grounded with supports.
- **Force Applications:**
- \( F_1 \) and \( F_2 \) are vertical downward forces applied at points \( E \) and \( D \), respectively.
- \( F_3 \) and \( F_4 \) are horizontal forces directed to the left, applied at points \( C \) and \( B \).
- **Beam Lengths:**
- The horizontal distances between points \( E \) to \( D \), and \( D \) to \( C \) are each 2 meters.
- The vertical sections from \( C \) to \( B \), and \( B \) to \( A \) are each 1.5 meters.
#### Structural Composition
- The truss is designed in a combination of triangular and rectangular shapes, maximizing its ability to bear loads efficiently.
- A triangular shape is formed between joints \( E, D, \) and \( G \), as well as between \( D, C, \) and \( H \).
#### Practical Application
Truss designs like this are common in bridges and roof supports, where they help distribute loads evenly across the structure, minimizing stress on any single point.
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