F be a field and F be a subfield E. The mapping : F[X]-> E defined by af₁ = f(a) called the evaluation homomorphism. ven the evaluation homomorphism $:C[x]-> C₁ aluate the given polynomial below. ote that (i)(i) =i² = -1. 2 Pi (2x²³²-x² + 3x − 2) where i = -1

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A: Inverse elements are 1 and -1

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A: We know that results

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Q: a-c

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