F be a field and F be a subfield E. The mapping : F[X]-> E defined by af₁ = f(a) called the evaluation homomorphism. ven the evaluation homomorphism $:C[x]-> C₁ aluate the given polynomial below. ote that (i)(i) =i² = -1. 2 Pi (2x²³²-x² + 3x − 2) where i = -1

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Let F be
a field and F be
a subfield
of
is
called the
E. The mapping &: F[X] -> E defined by aff) =f(a)
evaluation homomorphism.
Given the evaluation homomorphism $:C[x]-> C,
evaluate the given polynomial below.
Note that (i)(i) =¡² = -1.
2
Pi (2x²-x² + 3x-2) where t ² = -1
Transcribed Image Text:Let F be a field and F be a subfield of is called the E. The mapping &: F[X] -> E defined by aff) =f(a) evaluation homomorphism. Given the evaluation homomorphism $:C[x]-> C, evaluate the given polynomial below. Note that (i)(i) =¡² = -1. 2 Pi (2x²-x² + 3x-2) where t ² = -1
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