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f(-9) = 0 f(-1) = 0 f(2) = 2 f(4) = 4 f(6) = 3 lim f(x) =∞ lim f(x) =-∞ X--5+ lim f(x) = ∞ lim f(x) =1 ズ→-5- X--00 f'(-9) = 0 f'(-5) DNE f'(-1) = 0 f'(4) = 0 f'(x) > 0 on x E (-9,–5) u (–5,4) f'(x) < 0 on x € (-0, –9) U (4, 0)

f(-9) = 0 f(-1) = 0 f(2) = 2 f(4) = 4 f(6) = 3 lim f(x) =∞ lim f(x) =-∞ X--5+ lim f(x) = ∞ lim f(x) =1 ズ→-5- X--00 f'(-9) = 0 f'(-5) DNE f'(-1) = 0 f'(4) = 0 f'(x) > 0 on x E (-9,–5) u (–5,4) f'(x) < 0 on x € (-0, –9) U (4, 0)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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the second derivative has a typo, it is -1 instead of 1

?′′(?) < 0 ?? ? ∈ (−5,1) ∪ (2,6) 

The question is asking to sketch the graph with these provided information (SEE Image)

 

f(-9) = 0 f(-1) = 0 f (2) = 2 ƒ(4) = 4 f(6) = 3 lim_f(x) = lim, f(x) =-∞ X-5+ lim f(x) = 0 lim f(x) =1 = 00 X--5- X--00 X00 f'(-9) = 0 f'(-5) DNE f'(-1) = 0 f'(4) = 0 f'(x) > 0 on x e (-9,–5) u (-5,4) f'(x) < 0 on x E (-0, –9) U (4, 00) f"(-1) = 0 f"(-5) DNE f"(2) = 0 f"(6) = 0 f"(x) > 0 on x E (-∞0, –5) U (–1,2) U (6, ∞) f"(x) < 0 on x E (-5,1) U (2,6)
Transcribed Image Text:f(-9) = 0 f(-1) = 0 f (2) = 2 ƒ(4) = 4 f(6) = 3 lim_f(x) = lim, f(x) =-∞ X-5+ lim f(x) = 0 lim f(x) =1 = 00 X--5- X--00 X00 f'(-9) = 0 f'(-5) DNE f'(-1) = 0 f'(4) = 0 f'(x) > 0 on x e (-9,–5) u (-5,4) f'(x) < 0 on x E (-0, –9) U (4, 00) f"(-1) = 0 f"(-5) DNE f"(2) = 0 f"(6) = 0 f"(x) > 0 on x E (-∞0, –5) U (–1,2) U (6, ∞) f"(x) < 0 on x E (-5,1) U (2,6)
Snipping To 10 -8 -6 -4 -2 2. 4.6 .8. 10 10. -8 . -6 . -4. -2 -2 -4 -6 -8 -10
Transcribed Image Text:Snipping To 10 -8 -6 -4 -2 2. 4.6 .8. 10 10. -8 . -6 . -4. -2 -2 -4 -6 -8 -10
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