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Express the term of Bernoulli's equation in the form of Energy/Volume. Show your steps in achieving this. Hint: Use density (p) to express volume

Express the term of Bernoulli's equation in the form of Energy/Volume. Show your steps in achieving this. Hint: Use density (p) to express volume

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Express the term of Bernoulli's equation in the form of Energy/Volume. Show your steps in achieving this. Hint: Use density (p) to express volume of Answer:
Transcribed Image Text:Express the term of Bernoulli's equation in the form of Energy/Volume. Show your steps in achieving this. Hint: Use density (p) to express volume of Answer:
moodlefkk.uitm.edu.my Home Dashboard My courses This course Moodle Guide for Students stion 6 With the aid of a diagram, starting from the Bernoulli's equation and Continuity equation, show that the fluid velocity (v) in a horizontal pipe measured using a pitot-static tube is given as: yet vered ked out of ag tion Pm v = 2gh Where: Pm = density of mercury (13600 kg/m³) p = density of the fluid h = head deflection of the mercury g = acceleration due to gravity The same pitot-static tube mentioned above is used to measure the volumetric flow rate of mineral oil (SG = 1.3) that is flowing through in a pipe having a diameter of 250 mm. If the head deflection of the manometer attached to the pitot-static tube is given as 7 cm determine the actual volumetric flow rate of the mineral oil in the pipeline. Take the coefficient of discharge as 0.96. Answer: ous page Finish attempL
Transcribed Image Text:moodlefkk.uitm.edu.my Home Dashboard My courses This course Moodle Guide for Students stion 6 With the aid of a diagram, starting from the Bernoulli's equation and Continuity equation, show that the fluid velocity (v) in a horizontal pipe measured using a pitot-static tube is given as: yet vered ked out of ag tion Pm v = 2gh Where: Pm = density of mercury (13600 kg/m³) p = density of the fluid h = head deflection of the mercury g = acceleration due to gravity The same pitot-static tube mentioned above is used to measure the volumetric flow rate of mineral oil (SG = 1.3) that is flowing through in a pipe having a diameter of 250 mm. If the head deflection of the manometer attached to the pitot-static tube is given as 7 cm determine the actual volumetric flow rate of the mineral oil in the pipeline. Take the coefficient of discharge as 0.96. Answer: ous page Finish attempL
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