Express the given product as a sum containing only sines or cosines. cos (20) cos (80) *** cos (20) cos (80) = (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.)

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
Question
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### Trigonometric Product to Sum Conversion

#### Problem Statement:

**Express the given product as a sum containing only sines or cosines:**

\[ \cos(2\theta) \cos(8\theta) \]

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#### Solution Box:

\[ \cos(2\theta) \cos(8\theta) = \text{[Your Answer Here]} \]

(Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.)

---

### Explanation:

In this exercise, we will convert the product of two cosine functions into a sum involving only sine or cosine functions. This type of problem often requires the use of trigonometric identities such as product-to-sum identities.

The product-to-sum identities for cosine are given by:

\[ \cos(A) \cos(B) = \frac{1}{2} [ \cos(A - B) + \cos(A + B) ] \]

Using this identity, let \( A = 2\theta \) and \( B = 8\theta \):

\[ \cos(2\theta) \cos(8\theta) = \frac{1}{2} [ \cos(2\theta - 8\theta) + \cos(2\theta + 8\theta) ] \]

Simplify the angles inside the cosine functions:

\[ \cos(2\theta) \cos(8\theta) = \frac{1}{2} [ \cos(-6\theta) + \cos(10\theta) ] \]

Using the property that \( \cos(-x) = \cos(x) \):

\[ \cos(2\theta) \cos(8\theta) = \frac{1}{2} [ \cos(6\theta) + \cos(10\theta) ] \]

Therefore, the final expression for \( \cos(2\theta) \cos(8\theta) \) as a sum of cosines is:

\[ \cos(2\theta) \cos(8\theta) = \frac{1}{2} \cos(6\theta) + \frac{1}{2} \cos(10\theta) \]

You can write your final answer in the provided solution box.

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Note: Ensure that you enter any simplified terms with any radicals, if present, and use integers or fractions for any numerical values in the final expression
Transcribed Image Text:--- ### Trigonometric Product to Sum Conversion #### Problem Statement: **Express the given product as a sum containing only sines or cosines:** \[ \cos(2\theta) \cos(8\theta) \] --- #### Solution Box: \[ \cos(2\theta) \cos(8\theta) = \text{[Your Answer Here]} \] (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) --- ### Explanation: In this exercise, we will convert the product of two cosine functions into a sum involving only sine or cosine functions. This type of problem often requires the use of trigonometric identities such as product-to-sum identities. The product-to-sum identities for cosine are given by: \[ \cos(A) \cos(B) = \frac{1}{2} [ \cos(A - B) + \cos(A + B) ] \] Using this identity, let \( A = 2\theta \) and \( B = 8\theta \): \[ \cos(2\theta) \cos(8\theta) = \frac{1}{2} [ \cos(2\theta - 8\theta) + \cos(2\theta + 8\theta) ] \] Simplify the angles inside the cosine functions: \[ \cos(2\theta) \cos(8\theta) = \frac{1}{2} [ \cos(-6\theta) + \cos(10\theta) ] \] Using the property that \( \cos(-x) = \cos(x) \): \[ \cos(2\theta) \cos(8\theta) = \frac{1}{2} [ \cos(6\theta) + \cos(10\theta) ] \] Therefore, the final expression for \( \cos(2\theta) \cos(8\theta) \) as a sum of cosines is: \[ \cos(2\theta) \cos(8\theta) = \frac{1}{2} \cos(6\theta) + \frac{1}{2} \cos(10\theta) \] You can write your final answer in the provided solution box. --- Note: Ensure that you enter any simplified terms with any radicals, if present, and use integers or fractions for any numerical values in the final expression
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