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Express the following numbers in rectangular form (real and imaginary). (a) 9 39°= +i (b) 20 -15° = (c) 14/145° = (d) 15 -147 = +1 +

Express the following numbers in rectangular form (real and imaginary). (a) 9 39°= +i (b) 20 -15° = (c) 14/145° = (d) 15 -147 = +1 +

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Express the following numbers in rectangular form (real and imaginary). (a) 9 39°= +i (b) 20 -15° = (c) 14 2 145° = (d) 15 2-147° = +1 Find the following expressions. The angle is in degrees and between-180° and +180°. (a) (27+j (26)) (19 - 104°)=40* (b) (1 216°) (-19+i (14)) = 40 (c) (-20+) (-17))/(2 159°) = (d) (12-25%)/(16+) (-30)) = Write the complex number z=(-1-√3)¹6 in polar form: z=r(cos+ i sin 6) where r= |and 6 = The angle should satisfy 0 ≤ 0 <2m. V What is the square root of i? (That is, what is Vi?) OA. -i OB.-1 Oc. (1+¹) D. (1 - i) E. Does not exist Consider the equation = (1+√31). Find the value of which satisfies this equation and which has the second smallest positive argument 0,0 <0 < 2. Express your answer as :=re where T= and 8= 6
Transcribed Image Text:Express the following numbers in rectangular form (real and imaginary). (a) 9 39°= +i (b) 20 -15° = (c) 14 2 145° = (d) 15 2-147° = +1 Find the following expressions. The angle is in degrees and between-180° and +180°. (a) (27+j (26)) (19 - 104°)=40* (b) (1 216°) (-19+i (14)) = 40 (c) (-20+) (-17))/(2 159°) = (d) (12-25%)/(16+) (-30)) = Write the complex number z=(-1-√3)¹6 in polar form: z=r(cos+ i sin 6) where r= |and 6 = The angle should satisfy 0 ≤ 0 <2m. V What is the square root of i? (That is, what is Vi?) OA. -i OB.-1 Oc. (1+¹) D. (1 - i) E. Does not exist Consider the equation = (1+√31). Find the value of which satisfies this equation and which has the second smallest positive argument 0,0 <0 < 2. Express your answer as :=re where T= and 8= 6
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