Express the following first-order system as a single higher-order differential equation and solve using the given initial conditions. Make sure to change the initial conditions appropriately. Evaluate the system at t = 1 and select the most approximate vector form. y₁ = 2y₁ + 4y2 y2 = 4y1 + 2y2 y₁ (0) = 2, y2 (0) = 3. Y1 (1) Y2 (1) ° [U 1167.244 1167.574
Express the following first-order system as a single higher-order differential equation and solve using the given initial conditions. Make sure to change the initial conditions appropriately. Evaluate the system at t = 1 and select the most approximate vector form. y₁ = 2y₁ + 4y2 y2 = 4y1 + 2y2 y₁ (0) = 2, y2 (0) = 3. Y1 (1) Y2 (1) ° [U 1167.244 1167.574
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question
![Express the following first-order system as a single higher-order
differential equation and solve using the given initial conditions.
Make sure to change the initial conditions appropriately. Evaluate
the system at t = 1 and select the most approximate vector form.
y₁ = 2y₁ +4y2
y2 = 4y1 + 2y2
y₁ (0) = 2, y2 (0) = 3.
O [31 (1)
L32 (1).
Y2
O [y₁ (1)
Y2
y₁ (1)]
1 (1)
Y2 (1).
=
=
-
=
[1167.244]
1167.574
1008.504
1008.640
852.515
852.724]
998.587
998.451](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5d315888-6dbb-4a1a-b612-e836b18e12f7%2F70815316-db0d-4638-b400-cc25a3808a73%2Fc2ihp0i_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Express the following first-order system as a single higher-order
differential equation and solve using the given initial conditions.
Make sure to change the initial conditions appropriately. Evaluate
the system at t = 1 and select the most approximate vector form.
y₁ = 2y₁ +4y2
y2 = 4y1 + 2y2
y₁ (0) = 2, y2 (0) = 3.
O [31 (1)
L32 (1).
Y2
O [y₁ (1)
Y2
y₁ (1)]
1 (1)
Y2 (1).
=
=
-
=
[1167.244]
1167.574
1008.504
1008.640
852.515
852.724]
998.587
998.451
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