Express the confidence interval (57.5 % , 68.5 % ) in the form of p + ME.

Q: A survey of 800 women shoppers found that 17% of them shop on impulse what is the 98% confidence…

A: Sol:- To calculate the 98% confidence interval for the proportion of women shoppers who shop on…

Q: Recently an antibody study showed that the real number of people that have been infected by the…

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Q: In a sample of 120 adults, 114 had children. Construct a 99% confidence interval for the true…

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Q: Out of 200 people sampled, 168 had kids. Based on this, construct a 90% confidence interval for the…

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Q: Express the confidence interval 46.9%<p<57.5% in the form of ˆp±ME.

A:

Q: In a sample of 270 adults, 151 had children. Construct a 90% confidence interval for the true…

A: Given that  Sample size n =270 Favorable cases x =151 Sample proportion p^=x/n  =151/270 =0.5593

Q: A survey of 425 randomly selected students at one university found that 300 students think they…

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Q: Express the confidence interval (55.6%,69.6%) in the form of ˆp±ME  then express it in trilnear…

A: It is given that , The confidence interval =(55.6%,69.6%) Aim: To obtain the confidence interval in…

Q: Out of 600 people sampled, 486 had kids. Based on this, construct a 95% confidence interval for the…

A: It is given that  Favourable cases, X = 486 Sample size, n = 600

Q: A new fertilizer was applied to the soil of 276 bean plants. 24% showed increased growth. Find the…

A: Given Data: p=0.24 n=276   z-value corresponding to 95% Confidence level=1.96

Q: The confidence interval was (36,45) What was the margin of error? What was the point estimate

A: Answer: From the given data, The confidence interval = (36,45)

Q: A recent study of 2700 children randomly selected found 21​% of them deficient in vitamin D. ​…

A: Given that, 2700 children randomly selected found 21​% of them deficient in vitamin D. n=2700p^=0.21…

Q: 95% confidence interval from (0.08, 0.14) when computing the difference between California and…

A: Some people are interested in legalizing weed. A research wanted to compare responses between…

Q: Express the confidence interval (10.5 % , 28.3 % ) in the form of p + E.

A: Given The confidence interval (10.5%, 28.3%) Lower limit=10.5% Upper limit = 28.3% p^ = (Lower…

Q: Express the confidence interval 81.9%.   ±.   4.6%.  in interval form.

A: Confidence interval is the estimate of the interval of an unknown population parameter. It provides…

Q: Express the confidence interval 48.3 % <p < 60.9 % in the form of p+ ME. %土

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Q: In a sample of 290 adults, 191 had children. Construct a 95% confidence interval for the true…

A: 0.604 &lt; p &lt; 0.713 Explanation:Approach to solving the question:To construct a 95% confidence…

Q: In a sample of 270 adults, 173 had children. Construct a 99% confidence interval for the true…

A: The sample size n= 270. The sample proportion is 173/270. The absolute value of Zα/2 is 2.5758 using…

Q: In a sample of 360 adults, 245 had children. Construct a 99% confidence interval for the true…

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Q: In a sample of 290 adults, 261 had children. Construct a 95% confidence interval for the true…

A: Given : Sample Size, n = 290 Number of successes, x = 261

Q: In a sample of 550 adults, 512 had children. Construct a 99% confidence interval for the true…

A: Given X=512 n=550

Q: In a random sample of 500 Americans, 50% indicated that they have a cat for a pet. Estimate with 95%…

A: Given information

Q: Ethan is surveying students who are interested in watching television (TV) shows. Ethan has surveyed…

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Q: In a sample of 350 adults, 277 had children. Construct a 99% confidence interval for the true…

A: Sample size, Number of adults having children, Confidence level is .

Q: A survey conducted by Sallie Mae and Gallup of 1250 respondents found that 875 students paid for…

A: Solution: Given information: n= 1250 Sample size of respondentsx= 875 students paid for their…

Q: The drug OxyContin is used to treat pain, but it is dangerous because it is addictive and can be…

A: Given,n=278x=76p^=xnp^=76278=0.2731-p^=1-0.273=0.727α=1-0.90=0.1α2=0.05Z0.05=1.645  (from Z-table)

Q: The First National Bank of Wilson has 620 checking account customers. A recent sample of 70 of these…

A: Given that,N = 620n = 70x = 37Confidence interval(c) = 0.95The formula of the margin of error…

Q: Express the confidence interval (14.1 %, 20.1 %) in the form of p + ME. % ± R

A: Given confidence interval is(14.1%,20.1%)Upper limit=20.1%Lower limit=14.1%

Q: An internet service provider sampled 1000 of its customers, 189 of them experienced an interruption…

A: It is given that sample size (n) is 1000 and x is 189.

Q: Suppose that a garage finds that 42 customers of 142 customers samples get their oil changes on…

A: The objective of this question is to find the lower bound of the 98% confidence interval for the…

Q: A motorcycle dealer with the "Hd" brand wants to know the percentage of students in the city "X" who…

A: We have to find confidence interval.

Q: A random sample of 100 employees at a company shows that 42 drive US made automobiles (the rest…

A: A random sample of 100 employees at a company shows that 42 drives US made automobiles  p = Sample…

Q: nutritionist

A: Please refer to the image below

Q: Fatema computed a 95% confidence interval for the average time (in minutes) spent on social…

A: Given that, Fatema computed a 95% confidence interval for the average time spent on social…

Q: Suppose that a garage finds that 42 customers of 142 customers samples get their oil changes on…

A: The objective of this question is to find the lower bound of the 98% confidence interval for the…

Q: In a sample of 300 adults, 267 had children. Construct a 90% confidence interval for the true…

A: To construct a 90% confidence interval for the population proportion, we'll use the formula for the…

Q: The drug Ziljac is used to treat hypertension. In a clinical test, 4.9% of 290 Ziljac users…

A:

Q: The mileage a car got on 5 trips from Greenwood to Greenville was used to create a 90% confidence…

A: Solution-: Given: The 90% C.I. for the true mean mileage of such trips is (32.32,38.32) The…

Q: The National Center for Education Statistics reported that 47% of college students work to pay for…

A: Given :-   P = 47% =0.47 P=0.47 n=450   Formula :-   confidence interval =P-zαP1-Pn   ,…

Q: A survey found that 611 out of 663 college graduates cannot correctly spell the word aluminum. Find…

A: Given that  A survey found that 611 out of 663 college graduates cannot correctly spell the word…

Q: If n=510 and p (p-hat) =0.47, find the margin of error at a 90% confidence level Give your answer as…

A:

Q: Suppose that a garage finds that 30 customers of 138 customers samples get their oil changes on…

A: The objective of this question is to find the upper bound of the 98% confidence interval for the…

Q: Most married couples have two or three personality preferences in common. A random sample of 384…

A: Given X1=130 X2=200 n1=384 n2=574

Q: The mileage a car got on 5 trips from Greenwood to Greenville was used to create a 90% confidence…

A: Solution Given that 90% confidence interval is​ (32.32, 38.32).

Q: Express the confidence interval 20.1%<p<33.1% in the form of ˆp±E.

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Q: In a sample of 470 adults, 306 had children. Construct a 99% confidence interval for the true…

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Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.