Express the confidence interval (57.5 % , 68.5 % ) in the form of p + ME.
Q: A survey of 800 women shoppers found that 17% of them shop on impulse what is the 98% confidence…
A: Sol:- To calculate the 98% confidence interval for the proportion of women shoppers who shop on…
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Q: In a sample of 120 adults, 114 had children. Construct a 99% confidence interval for the true…
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Q: Out of 200 people sampled, 168 had kids. Based on this, construct a 90% confidence interval for the…
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Q: Express the confidence interval 46.9%<p<57.5% in the form of ˆp±ME.
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Q: In a sample of 270 adults, 151 had children. Construct a 90% confidence interval for the true…
A: Given that Sample size n =270 Favorable cases x =151 Sample proportion p^=x/n =151/270 =0.5593
Q: A survey of 425 randomly selected students at one university found that 300 students think they…
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Q: Express the confidence interval (55.6%,69.6%) in the form of ˆp±ME then express it in trilnear…
A: It is given that , The confidence interval =(55.6%,69.6%) Aim: To obtain the confidence interval in…
Q: Out of 600 people sampled, 486 had kids. Based on this, construct a 95% confidence interval for the…
A: It is given that Favourable cases, X = 486 Sample size, n = 600
Q: A new fertilizer was applied to the soil of 276 bean plants. 24% showed increased growth. Find the…
A: Given Data: p=0.24 n=276 z-value corresponding to 95% Confidence level=1.96
Q: A recent study of 2700 children randomly selected found 21% of them deficient in vitamin D. …
A: Given that, 2700 children randomly selected found 21% of them deficient in vitamin D. n=2700p^=0.21…
Q: 95% confidence interval from (0.08, 0.14) when computing the difference between California and…
A: Some people are interested in legalizing weed. A research wanted to compare responses between…
Q: Express the confidence interval (10.5 % , 28.3 % ) in the form of p + E.
A: Given The confidence interval (10.5%, 28.3%) Lower limit=10.5% Upper limit = 28.3% p^ = (Lower…
Q: Express the confidence interval 81.9%. ±. 4.6%. in interval form.
A: Confidence interval is the estimate of the interval of an unknown population parameter. It provides…
Q: Express the confidence interval 48.3 % <p < 60.9 % in the form of p+ ME. %土
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Q: In a sample of 290 adults, 191 had children. Construct a 95% confidence interval for the true…
A: 0.604 < p < 0.713 Explanation:Approach to solving the question:To construct a 95% confidence…
Q: In a sample of 270 adults, 173 had children. Construct a 99% confidence interval for the true…
A: The sample size n= 270. The sample proportion is 173/270. The absolute value of Zα/2 is 2.5758 using…
Q: In a sample of 360 adults, 245 had children. Construct a 99% confidence interval for the true…
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Q: In a sample of 290 adults, 261 had children. Construct a 95% confidence interval for the true…
A: Given : Sample Size, n = 290 Number of successes, x = 261
Q: In a sample of 550 adults, 512 had children. Construct a 99% confidence interval for the true…
A: Given X=512 n=550
Q: In a random sample of 500 Americans, 50% indicated that they have a cat for a pet. Estimate with 95%…
A: Given information
Q: Ethan is surveying students who are interested in watching television (TV) shows. Ethan has surveyed…
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Q: In a sample of 350 adults, 277 had children. Construct a 99% confidence interval for the true…
A: Sample size, Number of adults having children, Confidence level is .
Q: A survey conducted by Sallie Mae and Gallup of 1250 respondents found that 875 students paid for…
A: Solution: Given information: n= 1250 Sample size of respondentsx= 875 students paid for their…
Q: The drug OxyContin is used to treat pain, but it is dangerous because it is addictive and can be…
A: Given,n=278x=76p^=xnp^=76278=0.2731-p^=1-0.273=0.727α=1-0.90=0.1α2=0.05Z0.05=1.645 (from Z-table)
Q: The First National Bank of Wilson has 620 checking account customers. A recent sample of 70 of these…
A: Given that,N = 620n = 70x = 37Confidence interval(c) = 0.95The formula of the margin of error…
Q: Express the confidence interval (14.1 %, 20.1 %) in the form of p + ME. % ± R
A: Given confidence interval is(14.1%,20.1%)Upper limit=20.1%Lower limit=14.1%
Q: An internet service provider sampled 1000 of its customers, 189 of them experienced an interruption…
A: It is given that sample size (n) is 1000 and x is 189.
Q: Suppose that a garage finds that 42 customers of 142 customers samples get their oil changes on…
A: The objective of this question is to find the lower bound of the 98% confidence interval for the…
Q: A motorcycle dealer with the "Hd" brand wants to know the percentage of students in the city "X" who…
A: We have to find confidence interval.
Q: A random sample of 100 employees at a company shows that 42 drive US made automobiles (the rest…
A: A random sample of 100 employees at a company shows that 42 drives US made automobiles p = Sample…
Q: Suppose that a garage finds that 42 customers of 142 customers samples get their oil changes on…
A: The objective of this question is to find the lower bound of the 98% confidence interval for the…
Q: In a sample of 300 adults, 267 had children. Construct a 90% confidence interval for the true…
A: To construct a 90% confidence interval for the population proportion, we'll use the formula for the…
Q: The mileage a car got on 5 trips from Greenwood to Greenville was used to create a 90% confidence…
A: Solution-: Given: The 90% C.I. for the true mean mileage of such trips is (32.32,38.32) The…
Q: The National Center for Education Statistics reported that 47% of college students work to pay for…
A: Given :- P = 47% =0.47 P=0.47 n=450 Formula :- confidence interval =P-zαP1-Pn ,…
Q: A survey found that 611 out of 663 college graduates cannot correctly spell the word aluminum. Find…
A: Given that A survey found that 611 out of 663 college graduates cannot correctly spell the word…
Q: If n=510 and p (p-hat) =0.47, find the margin of error at a 90% confidence level Give your answer as…
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Q: Suppose that a garage finds that 30 customers of 138 customers samples get their oil changes on…
A: The objective of this question is to find the upper bound of the 98% confidence interval for the…
Q: The mileage a car got on 5 trips from Greenwood to Greenville was used to create a 90% confidence…
A: Solution Given that 90% confidence interval is (32.32, 38.32).
Q: Express the confidence interval 20.1%<p<33.1% in the form of ˆp±E.
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Q: In a sample of 470 adults, 306 had children. Construct a 99% confidence interval for the true…
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- In a sample of 460 adults, 281 had children. Construct a 90% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three places < p <Express the confidence interval 89.4 % + 4.4 % in interval form. Express the answer in decimal format (do not enter as percents). Question Help: DVideo Submit Question 吕0 888 F6 F7 F4 F5 F2 F3 * @ #3 24 8 2 3 R Y w/Construct a 96% confidence interval if x=75 and n=200. Round your answers to 3 decimal places.
- A random sample of high school seniors were asked whether they were applying for college. The resulting confidence interval for the proportion of students applying for college is (0.65,0.69). What is the margin of error?Researchers are studying whether the proportion of homeschooled children in district 1 (considered 1) is less than the proportion of homeschooled children in neighboring district 2 (considered as 2). To test the theory info was gathered: district 1 had 600 students of which 90 were homeschooled. District 2 had 550 students of which 99 were homeschooled. What is the 95% confidence interval for the difference proportion between district 1 and 2? A. (-0.086, 0.026) B. (0.143, 0.217) C. (0.113, 0.187)Express the confidence interval (57.8%,71%) in the form of p ± E.
- Suppose that a garage finds that 30 customers of 138 customers samples get their oil changes on time. Find a 98% confidence interval of the true proportion. What is the upper bound of the confidence interval? (round to 4 decimal places)A random sample of 1700 car owners in a particular city found 816 car owners who received a speeding ticket this year. Using the Wilson "plus four" technique, find a 95% confidence interval for the true percent of car owners in this city who received a speeding ticket this year. Express your results to the nearest hundredth of a percent.A random sample of 75 customers was polled. .626 and the 95% confidence interval
- In a sample of 360 adults, 266 had children. Construct a 95% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three placesIn a sample of 510 adults, 281 had children. Construct a 95% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three placesRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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