If we observe the first productions of expr, id is presented for both expr -> id=expr and expr -> term term_tail. So, given grammar is not LL(1) grammar.Modify the grammar above to obtain an equivalent grammar that is LL(1). exprterm_tailtermfactor_tailid = expr | term term_tail+ term term_tail | Efactor factor_tail→ * factor factor_tail | efactor → (expr) | idExplain why the grammar above is not LL(1). Be specific.

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Answered: expr term_tail term → id = expr | term…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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If we observe the first productions of expr, id is presented for both expr -> id=expr and expr -> term term_tail. So, given grammar is not LL(1) grammar.

Modify the grammar above to obtain an equivalent grammar that is LL(1).

expr
term_tail
term
factor_tail
id = expr | term term_tail
+ term term_tail | E
factor factor_tail
→ * factor factor_tail | e
factor → (expr) | id
Explain why the grammar above is not LL(1). Be specific.

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