ExponentialFunctiony=3,500 (1.12)y = 10,000 (0.90)y = 5(1.025)y=160(0.79)ty=2(0.85)t = 1,950 (1.875)*Growth (G)orDecay(D)?Rate (%)e. What will your score be when you takeTWO MORE quizzes?

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Answered: Exponential Function y=3,500 (1.12) y =…

Exponential Function y=3,500 (1.12) y = 10,000(0.90)t y=5(1.025) y=160 (0.79) y=2(0.85) t = 1,950(1.875)¹ Growth (G) or Decay(D)? Rate (%)

Trigonometry (11th Edition)

11th Edition

ISBN:9780134217437

Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels

Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels

Chapter1: Trigonometric Functions

Section: Chapter Questions

Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.

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Question

Exponential
Function
y=3,500 (1.12)
y = 10,000 (0.90)
y = 5(1.025)
y=160(0.79)t
y=2(0.85)
t = 1,950 (1.875)*
Growth (G)
or
Decay(D)?
Rate (%)
e. What will your score be when you take
TWO MORE quizzes?

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The exponential growth of the deer population in the country can be calculated using the model T=20,000(1+.08)^n where 20,000 is the initial deer population and .08 is the rate of growth. T is the total population after n years have passed. Question content area bottom Part 1 (a) Predict the total population after 2 yr. The total population after 2 yr is about enter your response here. (Round to the nearest thousand as needed.) Part 2 (b) If the initial population was 10,000 and the growth rate was .12, approximately how many deer would be present after 3 yr? After 3 yr approximately enter your response here deer would be present. (Round to the nearest thousand as needed.) Part 3 (c) How many additional deer can we expect in 5 yr if the initial population is 45,000 and the current growth rate is .07? We can expect about enter your response here additional deer. (Round to the nearest thousand as needed.)
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