Exploring permutations. The formula for the number of ways to arrange n objects is n! = nX(n-1)x…x2X1. This exercise walks you through the derivation of this formula for a couple of special cases. A small company has five employees: Anna, Ben, Carl, Damian, and Eddy. There are five parking spots in a row at the company, none of which are assigned, and each day the employees pull into a random parking spot. That is, all possible orderings of the cars in the row of spots are equally likely. A) On a given day, what is the probability that the employees park in alphabetical order? B) If the alphabetical order has an equal chance of occuring relative to all other possible orderings, how many ways must there be to arrange the five cars? C) Now consider a sample of 8 employees instead. How many possible ways are there to order these 8 employees cars?
Exploring permutations. The formula for the number of ways to arrange n objects is n! = nX(n-1)x…x2X1. This exercise walks you through the derivation of this formula for a couple of special cases.
A small company has five employees: Anna, Ben, Carl, Damian, and Eddy. There are five parking spots in a row at the company, none of which are assigned, and each day the employees pull into a random parking spot. That is, all possible orderings of the cars in the row of spots are equally likely.
A) On a given day, what is the
B) If the alphabetical order has an equal chance of occuring relative to all other possible orderings, how many ways must there be to arrange the five cars?
C) Now consider a sample of 8 employees instead. How many possible ways are there to order these 8 employees cars?
No. of parking spots =5
No. of people =5
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