Explanation of Solution Given information: The equation is z = xy and Calculation: Consider the equation. √ 2x³ + 2y³ = 3t² 3x² + 3y² 6t Differentiate above equation. 6x2 dx + 6y²5 dt z = xy² z = xy dx dt = 6x dx + 6y. dt = t-y x(x-y) (y² - xy) dy dt The solution of above simultaneous equation is, (x² − xy) dx = t - y dt dy dt = t-x y(y-x) dt - = t-x = 6 6t 2x³ + 2y³ = 31² 3x² + 3y² 6t =

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