Explanation of Solution Given: 1.234567 = 1.234567567567... Result used: The geometric series >) `ar"-1 (or) a + ar + ar² + is convergent if n=1 |r| < 1 and its sum is -"-, where a is the first term and ris the common ratio of the series. Calculation: Rewrite the number and express 1.234567 as follows, 1.234567 = 1.234 + 0.000567 1.234 + (0.00 67+ 0.000000567+ ·· ·) = 1.234 + 106 567 567 +...) 10° 567 (1) 1.234567 = 1.234 + 103n n=2 567 is geometric series with first term of the series is a Here, 567 103n n=: 106 and common ratio is r = 103 Since |r| < 1 and the Result stated above, the geometric series 567 is 103n n=2 convergent.

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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In the image attached, the geometric series I need to solve begins with "2" (n = 2). I'm not sure why it begins at 2, and not 1. Do you know why this series begins with 2? Let me know if you need more clarification!

Explanation of Solution
Given:
1.234567 = 1.234567567567...
Result used:
The geometric series >)
`ar"-1 (or) a + ar + ar² +
is convergent if
n=1
|r| < 1 and its sum is -"-, where a is the first term and ris the common
ratio of the series.
Calculation:
Rewrite the number and express 1.234567 as follows,
1.234567 = 1.234 + 0.000567
1.234 + (0.00
67+ 0.000000567+ ·· ·)
= 1.234 +
106
567
567
+...)
10°
567
(1)
1.234567 = 1.234 +
103n
n=2
567
is geometric series with first term of the series is a
Here,
567
103n
n=:
106
and common ratio is r =
103
Since |r| < 1 and the Result stated above, the geometric series
567
is
103n
n=2
convergent.
Transcribed Image Text:Explanation of Solution Given: 1.234567 = 1.234567567567... Result used: The geometric series >) `ar"-1 (or) a + ar + ar² + is convergent if n=1 |r| < 1 and its sum is -"-, where a is the first term and ris the common ratio of the series. Calculation: Rewrite the number and express 1.234567 as follows, 1.234567 = 1.234 + 0.000567 1.234 + (0.00 67+ 0.000000567+ ·· ·) = 1.234 + 106 567 567 +...) 10° 567 (1) 1.234567 = 1.234 + 103n n=2 567 is geometric series with first term of the series is a Here, 567 103n n=: 106 and common ratio is r = 103 Since |r| < 1 and the Result stated above, the geometric series 567 is 103n n=2 convergent.
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