Copper crystallizes into a face-centered cubic crystal structure. (a) How many copper atoms are there in one unit cell of copper crystal? (b) If the density of copper is 8.96 g/cm³, what is the edge-length of the unit cell in pm? (c) Calculate the atomic radius of copper in pm. (1 u = 1.6605 x 10-24 g; 1 pm = 10-10 cm)
Copper crystallizes into a face-centered cubic crystal structure. (a) How many copper atoms are there in one unit cell of copper crystal? (b) If the density of copper is 8.96 g/cm³, what is the edge-length of the unit cell in pm? (c) Calculate the atomic radius of copper in pm. (1 u = 1.6605 x 10-24 g; 1 pm = 10-10 cm)
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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 alt="18. Copper crystallizes into a face-centered cubic crystal structure. (a) How many copper atoms are there in
one unit cell of copper crystal? (b) If the density of copper is 8.96 g/cm³, what is the edge-length of the
unit cell in pm? (c) Calculate the atomic radius of copper in pm. (1 u = 1.6605 x 10-24 g; 1 pm = 10-10 cm)
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Transcribed Image Text:18. Copper crystallizes into a face-centered cubic crystal structure. (a) How many copper atoms are there in
one unit cell of copper crystal? (b) If the density of copper is 8.96 g/cm³, what is the edge-length of the
unit cell in pm? (c) Calculate the atomic radius of copper in pm. (1 u = 1.6605 x 10-24 g; 1 pm = 10-10 cm)
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3
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I don't understand this portion of the explanation:
d = Z x Ma3 x NAwere,d = densityZ = atoms per unit cellM = molar massa = edge lengthNa=
d = Z x Ma3 x NA8.96 gcm3 = 4 x 63.55 gmolea3 x 6.022 x 1023 1molea3 = 254.2 gmole5.3957 x 1024 gcm3 mole a3 = 4.7111 x 10-23 cm3a = 3.6117 x 10-8 cm
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