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Explain why the restriction n - 1 is necessary in the rule Choose the correct answer below. O O A. If the restriction was not there, then Sx D. - 1 The restriction is necessary since Sx dx = 10 dx = √x"dx 1 B. The restriction is necessary since x has a vertical asymptote at x = 0. - 1 C. If the restriction was not there, then fx ¹dx = xº + C = 1 + C but the derivative of 1 + C is not x¯1. - 1 2 dx = 1 n+1 n+1 X + C. +C which is not possible. ... + C, so the rule shown does not work.

Explain why the restriction n - 1 is necessary in the rule Choose the correct answer below. O O A. If the restriction was not there, then Sx D. - 1 The restriction is necessary since Sx dx = 10 dx = √x"dx 1 B. The restriction is necessary since x has a vertical asymptote at x = 0. - 1 C. If the restriction was not there, then fx ¹dx = xº + C = 1 + C but the derivative of 1 + C is not x¯1. - 1 2 dx = 1 n+1 n+1 X + C. +C which is not possible. ... + C, so the rule shown does not work.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Explain why the restriction n‡ - 1 is necessary in the rule · Sx²dx==1₁x²+¹ + + C. Choose the correct answer below. A. If the restriction was not there, then - 1 B. The restriction is necessary since x 1 fx¯¹dx C. If the restriction was not there, then D. The restriction is necessary since _n+1 dx = =-=-= + C which is not possible. has a vertical asymptote at x = 0. √x=¹dx = xº + C = 1+ C but the derivative of 1 + C is not x¯¹. - 1 -2 √x₁¹dx = -1/2x² + C, so the rule shown does not work.
Transcribed Image Text:Explain why the restriction n‡ - 1 is necessary in the rule · Sx²dx==1₁x²+¹ + + C. Choose the correct answer below. A. If the restriction was not there, then - 1 B. The restriction is necessary since x 1 fx¯¹dx C. If the restriction was not there, then D. The restriction is necessary since _n+1 dx = =-=-= + C which is not possible. has a vertical asymptote at x = 0. √x=¹dx = xº + C = 1+ C but the derivative of 1 + C is not x¯¹. - 1 -2 √x₁¹dx = -1/2x² + C, so the rule shown does not work.
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