Explain why the function is differentiable at the given point. f(x, y) = 3 +exycos(y), (,0) The partial derivatives aref (x, y) = and f(x, y) = ,so fx(π, 0) = and f,(,0) = . Both fx and fy are continuous functions, so f is differentiable at (,0).
Explain why the function is differentiable at the given point. f(x, y) = 3 +exycos(y), (,0) The partial derivatives aref (x, y) = and f(x, y) = ,so fx(π, 0) = and f,(,0) = . Both fx and fy are continuous functions, so f is differentiable at (,0).
Explain why the function is differentiable at the given point. f(x, y) = 3 +exycos(y), (,0) The partial derivatives aref (x, y) = and f(x, y) = ,so fx(π, 0) = and f,(,0) = . Both fx and fy are continuous functions, so f is differentiable at (,0).
Explain why the function is differentiable at the given point.
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
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