Explain why Newtons third law of Motion in not valid in case of moving charges?
Q: q = +1nC 1 cm 1 сm 60° 60° 1 cm 93 = -2nC %3D q2 = + 2nC
A: To determine the net force on +1 nC charge and its direction.given,q1=+1 nC=1×10-9 Cq2=+2 nC=2×10-9…
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Q: Two Charges of +4.0 nC and -1.0 nC are fixed to a baseline at a separation of 1.0 m. Where on the…
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Q: Three charges are arranged as shown in the figure below. Find the magnitude and direction of the…
A: Solution:Given:k = Coulomb's constant = 8.99 x 109 N.m2/C2 q1 = strength of charge 1 = -3.00 nCq2 =…
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Q: O Four charges are placed in the plane as indicated q, = 10 nC in r, = i + 2j, 93 = -2 nC in r3 =…
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Q: a proton at a particular distance from a charged particle is attracted with a given force, what…
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- Particles of charges +75 , +48 and -85 μC are places in a line (see the figure ) the center one is 0.35 m from each of the others calculate the net force on each charge due to the other two .Three charges on the x-axis as shown below, if the distancesare in centimeters, find the net force on the fourth charge on they-axis.Two charges +4 µC and +11 µC are placed along the x axis, with the first charge at the origin (x = 0) and the second charge at x = +1 m. Find the magnitude and direction of the net force on a -9 nC charge when placed at the following locations below. Overall Hint Review Section 5.3 Coulomb's Law. Use Coulomb's Law to calculate force due to each of two charges and add them together for the net force, minding the directions. For part (c), you will need to do the vector sum (more below). a. halfway between the two charges: magnitude of force is direction is Select an answer b. on the x axis at x = -0.5 m: magnitude of force is direction is Select an answer c. at the coordinate (x, y) = (1 m, 0.5 m) (half a meter above the +11 µC charge in a direction perpendicular to the line joining the two fixed charges): Hint for (c) Magnitude of force is degrees below -x axis. mN, and the direction is mN, and the mN, and the
- A) Find the x-component of the total force exerted on the third charge by the other two. B) Find the y-component of the total force exerted on the third charge by the other two. C) Find the magnitude of the total force acting on the third charge. D) Find the direction of the total force acting on the third charge.Three point charges are located on XY plane such that 4C on X axis at x=-1 m, 3 C on x axis at x=1m, -2 C on Y axis at y=1 m. Label direction of forces acting on 4C charge as follows.(use arrow heads to label direction) Force on 4C due -2C as F1. Force on 4C due to 3 C as F2.What is the magnitude of the force on the 1.0 nC charge in the Figure? (Answer in scientific notation and correct number of sig. figs)
- If two equal charges each of 1 C, were separated in air by a distance of 1 km (1km = 1000 m), what would be the value of the force between them? Identify also if it is repulsive or attractive force.Two charges +10 μC and +7 μC are placed along the x axis, with the first charge at the origin (x = 0) and the second charge at x = +1 m. Find the magnitude and direction of the net force on a -4 nC charge when placed at the following locations below. Overall Hint Review Section 5.3 Coulomb's Law. Use Coulomb's Law to calculate force due to each of two charges and add them together for the net force, minding the directions. For part (c), you will need to do the vector sum (more below). a. halfway between the two charges: magnitude of force is the direction is (in-x direction b. on the axis at x = -0.5 m: magnitude of force is direction is (in +x directio Hint for (c) c. at the coordinate (x, y) = (1 m, 0.5 m) (half a meter above the +7 μC charge in a direction perpendicular to the line joining the two fixed charges): Magnitude of force is mN, and the direction is mN, and degrees below-x axis. mN, and the