explain why astronomers call such an object a blackbody?
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Q: collisions transfer energy
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A: We can apply Wien's law.
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A: If the temperature of a blackbody increases, the peak wavelength will increase as well
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A: A blackbody is an idealized physical body that absorbs all incident electromagnetic radiation,…
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An idealized radiating object does not reflect or scatter any radiation but instead absorbs all of
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- You’re in a potions class and your friend has a bubbling cauldron of soup. You measure with a super-magic thermometer that reads 1808 K. Your skin is measured at 33 °C. Assume both examples radiate like a blackbody. a) What wavelength does the soup radiate at maximum intensity and which region of the electromagnetic spectrum does this wavelength correspond? b) Repeat part a) for your skin.Visible light is O a large portion of the full electromagnetic spectrum. O the only phenomenon presented during the lectures on Light. O a small portion of the full electromagnetic spectrum. O a portion of the electromagnetic spectrum that ranges from microwaves to ultraviolet light ... .. ..*** ...As you may well know, placing metal objects inside a microwave oven can generate sparks. Two of your friends are arguing over the cause of the sparking, with one stating that the microwaves "herd" electrons into "pointy" areas of the metal object, from which the electrons jump from one part of the object to another. The other friend says that the sparks are caused by the photoelectric effect. Prove or disprove the latter idea using basic physics. Suppose the typical work function of the metal is roughly 3.630 × 10-19 J. Calculate the maximum wavelength in angstroms of the radiation that will eject electrons from the metal. wavelength: Å
- d&eElectrons are ejected from a metallic surface with speeds ranging up to 4.1 × 105 m/s when light with a wavelength of 630nm is used. What is the cutoff frequency for this surface? Express your answer in terms of 1014 Hz and round it to the nearest hundredth. For example, if you get 1.234 x 1014 Hz, you type in 1.23. (Hint: you should first calculate the work function of the surface.) Use h=6.626x1034 Js; c=3 x108 m/s. ; me=9.11x10-31kg Js; c=3 x108 m/s. ; me=9.11x1031kgConsider a photon with energy 1.5 eV. 1. What is its wavelength in nanometers? 2. What is its frequency in hertz? 3. What type of electromagnetic radiation is it?
- If you double the temperature of a blackbody, by what factor will the total energy radiated per second per square meter increase?Remember the wave equation is v = lambda - f For electromagnetic waves traveling in a vacuum, they all travel at the speed of light c = 2.998 * 10 ^ 8 * m / s . An ultraviolet wave from the Sun traveling at the speed of light has a wavelength of 3 * 10 ^ - 8 * m . Calculate the frequency of this wave 8.85 * 10 ^ 15 * Hz; 2.33 * 10 ^ 13 * Hz; 9.99 * 10 ^ 13 * Hz; 9.99 * 10 ^ 15 * HzCalculate the wavelength (λ) for an ultraviolet photon having a frequency ν = 2.33 × 1015 s–1. Express your answer in units of nanometers.