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EXPLAIN THIS SOLUTION USING ONLY WORDS SO I CAN UNDERSTAND IT BETTER

EXPLAIN THIS SOLUTION USING ONLY WORDS SO I CAN UNDERSTAND IT BETTER

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Hello, Please EXPLAIN THIS SOLUTION USING ONLY WORDS SO I CAN UNDERSTAND IT BETTER. Thank You. Hoping you will answer it the way i asked.

example: in the first part of this diffetential equation, we should get the .............

 

5. = 5. = 5 (6PM) 5. => 5 ED -1 6D+1 (601) (60+) sl (GDJ² -1² Sin 3t → Xp(t) = 5 sin 37 (CD + 1) sin 3t 360²-1 (60+ 1) sin 3t 36(-32) 1 5 x E5 = 5 (60+1) -324-1 sin 3t (6D+1) 36x (19) - GD+1 -325 کر ان کی کار لانے والی -15 (ad Sin36 ㅗ laddade 65 5n3t sin 37 sin st (60 sin3t + sin 3t) + sun 3t) -1 (6. 3 cos 3t + sin3t) 45 Xp(t) = (18 cos 3t + sinst) 65 •The general solution given by x (t) = xc (t) + Xp (t) -*XXL+) = (₁ ett + C²₂2e² Ĵ 0 ۲۱ = (18000 36 | singt Junnila
Transcribed Image Text:5. = 5. = 5 (6PM) 5. => 5 ED -1 6D+1 (601) (60+) sl (GDJ² -1² Sin 3t → Xp(t) = 5 sin 37 (CD + 1) sin 3t 360²-1 (60+ 1) sin 3t 36(-32) 1 5 x E5 = 5 (60+1) -324-1 sin 3t (6D+1) 36x (19) - GD+1 -325 کر ان کی کار لانے والی -15 (ad Sin36 ㅗ laddade 65 5n3t sin 37 sin st (60 sin3t + sin 3t) + sun 3t) -1 (6. 3 cos 3t + sin3t) 45 Xp(t) = (18 cos 3t + sinst) 65 •The general solution given by x (t) = xc (t) + Xp (t) -*XXL+) = (₁ ett + C²₂2e² Ĵ 0 ۲۱ = (18000 36 | singt Junnila
Olfa + Gdx dt corresponding •We can get the roots by using it's auxiliary equation 1²+Gm+80 - m² + am + 2m + 8 +0 Jm(m+a) + 2 (m +a)=0 - (m+4) (m+ 2) = 0 => either (m+2) = + 8x = 6 sin 36 "If m+2=0 ; m = -2 mtado;m - 4 = 5. So, the complementary solution is Xect) <c₁e-46 +C₂ ezt = 5 x 5. or (m+4)=0 • The particular solution Xp(t)= 1 0²16078 1 D² too ty "]Roots -9+60+8 -3²+60+8 5 sin3t sin 3t ; sin 3t - Equation 1 where is given by C₁ and constants Equation 2 P(D²) C₂ are arbitrary · sin at = F(-aª) sin at
Transcribed Image Text:Olfa + Gdx dt corresponding •We can get the roots by using it's auxiliary equation 1²+Gm+80 - m² + am + 2m + 8 +0 Jm(m+a) + 2 (m +a)=0 - (m+4) (m+ 2) = 0 => either (m+2) = + 8x = 6 sin 36 "If m+2=0 ; m = -2 mtado;m - 4 = 5. So, the complementary solution is Xect) <c₁e-46 +C₂ ezt = 5 x 5. or (m+4)=0 • The particular solution Xp(t)= 1 0²16078 1 D² too ty "]Roots -9+60+8 -3²+60+8 5 sin3t sin 3t ; sin 3t - Equation 1 where is given by C₁ and constants Equation 2 P(D²) C₂ are arbitrary · sin at = F(-aª) sin at
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