Explain the calculations below by relating the values of the calculation to various laws in electrical engineering Parallel resistive circuit 1/Req= 1/R1+1/R2+1/R3+1/R4 1/Req= 1/3+1/5.2+1/3.3+1/4.1 1/Req= 1/3+1/5.2+1/3.3+1/4.1 1/Req= 1.073Ω Req= 0.932 Ω I1= VT/R1=9/3= 3amps I2= VT/R2=9/5.2= 1.73amps I3= VT/R3=9/3.3= 2.73amps I4= VT/R4=9/4.1= 2.20amps IT= 3+1.73+2.73+2.20= 9.66amps Power dissipation through each resistor P1=I21×R1= (3)2×3=27watt P2=I22×R2= (1.73)2×5.2= 15.56watt P3=I23×R3= (2.73)2×3.3=24.60watt P4=I24×R4= (2.20)2×4.1= 19.84watt Total circuit power P=VI P= 9V×9.66amps P=86.94watts
Explain the calculations below by relating the values of the calculation to various laws in electrical engineering
Parallel resistive circuit
1/Req= 1/R1+1/R2+1/R3+1/R4
1/Req= 1/3+1/5.2+1/3.3+1/4.1
1/Req= 1/3+1/5.2+1/3.3+1/4.1
1/Req= 1.073Ω
Req= 0.932 Ω
I1= VT/R1=9/3= 3amps
I2= VT/R2=9/5.2= 1.73amps
I3= VT/R3=9/3.3= 2.73amps
I4= VT/R4=9/4.1= 2.20amps
IT= 3+1.73+2.73+2.20= 9.66amps
Power dissipation through each resistor
P1=I21×R1= (3)2×3=27watt
P2=I22×R2= (1.73)2×5.2= 15.56watt
P3=I23×R3= (2.73)2×3.3=24.60watt
P4=I24×R4= (2.20)2×4.1= 19.84watt
Total circuit power
P=VI
P= 9V×9.66amps
P=86.94watts
converting resistor to inductance
G1=1/R1=1/3=0.33mho
G2=1/R2=1/5.2=0.19mho
G3=1/R3=1/3.3=0.30mho
G4=1/R4=1/4.1=0.24mho
Geq= 0.33+0.19+0.30+0.24=1.06mho
I1=VG1=9×0.33=2.97Amps
I2=VG2=9×0.19=1.71Amps
I3=VG3=9×0.30=2.70Amps
I4=VG4=9×0.24=2.16Amps
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