Explain how to use the figure to solve the equation 2 cos(x) - 1 = 0. y = cos x The equation 2 cos(x) - 1 - 0 is equivalent to the equation cos(x) - . So the intersection points of y = cos(x) and y= represent the solution of the equation 2 cos(x) – 1 = 0. State the solutions of the equation on the interval (-27, 27). (Enter your answers as a comma-separated list.)
Explain how to use the figure to solve the equation 2 cos(x) - 1 = 0. y = cos x The equation 2 cos(x) - 1 - 0 is equivalent to the equation cos(x) - . So the intersection points of y = cos(x) and y= represent the solution of the equation 2 cos(x) – 1 = 0. State the solutions of the equation on the interval (-27, 27). (Enter your answers as a comma-separated list.)
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Transcribed Image Text:**How to Solve the Equation 2 cos(x) - 1 = 0 Using the Graph**
**Graph Explanation:**
The graph depicts the cosine function \( y = \cos(x) \), shown as a smooth, wavy line fluctuating between -1 and 1. Two labeled intersections indicate that \( y = \frac{1}{2} \) serves as a horizontal line intersecting the cosine curve.
Key points marked on the graph include:
- \( x = \frac{\pi}{3} \)
- \( x = \frac{5\pi}{3} \)
- \( x = -\frac{\pi}{3} \)
- \( x = -\frac{5\pi}{3} \)
**Explanation and Solution Steps:**
1. The equation \( 2 \cos(x) - 1 = 0 \) is equivalent to \( \cos(x) = \frac{1}{2} \).
2. Intersection points of \( y = \cos(x) \) and \( y = \frac{1}{2} \) are the solutions we seek.
3. Thus, the \( x \)-values corresponding to these intersections are the solutions to the equation.
**Formulation:**
- The equation \( \cos(x) = \frac{1}{2} \) gives the solution values for \( x \).
- The solutions within the interval \((-2\pi, 2\pi)\) are \( x = -\frac{5\pi}{3}, -\frac{\pi}{3}, \frac{\pi}{3}, \frac{5\pi}{3} \).
These solutions specify that the cosine curve intersects the horizontal line \( y = \frac{1}{2} \) at these points within the defined interval.
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