Explain how the answers in red are right

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Explain how the answers in red are right
5:30
◄ Search
Density (d) =
We know, at STP - 1 mol. of a gas occupies a volume
= 22.4 L
Total no. of moles =
P =
Step3
c)
Sample Pressure
(P)
No.
1
2
3
nRT
V
4
5
0.54
atm.
1 atm. 0.045 mol-0.082
1 tm.
1.57
atm.
GON torr
-0.8
atm.
-; V=
380 torr
-0.5
alm
atm.
Volume (V)
mol K
- 1.09L
3L
1 L
R= Universal gas constant = 0.0821
7L
15 L
1 atm. = 760 torr
PV
nRT
P
298
Mass of the substance
Molar Mass
; T =
Number
of moles
(n)
29.
44 mol
-0.045
0.05
0.07
0.223
0.306
Mass (m)
Volume (V)
nR
?
25°C = 298 K
Temperature Mass MW
(T)
(K)
400 K
0°C -273 K
306.24 K
298 K
I
; Mass = n * MW
2 g
6.44
R
44
7.3 g. 7.39
0.05 mal
14.27
mal
92
64
1.224 4
√x
L-atm.
mol.K
Density Volume
(K/L)
sample
would have
at STP
1.02 L
1.09 €
-1.83
2.43
2.04
0.082
0.05 mol.
1.12 L
1.57 L
5L
6.85
DO
8
Transcribed Image Text:5:30 ◄ Search Density (d) = We know, at STP - 1 mol. of a gas occupies a volume = 22.4 L Total no. of moles = P = Step3 c) Sample Pressure (P) No. 1 2 3 nRT V 4 5 0.54 atm. 1 atm. 0.045 mol-0.082 1 tm. 1.57 atm. GON torr -0.8 atm. -; V= 380 torr -0.5 alm atm. Volume (V) mol K - 1.09L 3L 1 L R= Universal gas constant = 0.0821 7L 15 L 1 atm. = 760 torr PV nRT P 298 Mass of the substance Molar Mass ; T = Number of moles (n) 29. 44 mol -0.045 0.05 0.07 0.223 0.306 Mass (m) Volume (V) nR ? 25°C = 298 K Temperature Mass MW (T) (K) 400 K 0°C -273 K 306.24 K 298 K I ; Mass = n * MW 2 g 6.44 R 44 7.3 g. 7.39 0.05 mal 14.27 mal 92 64 1.224 4 √x L-atm. mol.K Density Volume (K/L) sample would have at STP 1.02 L 1.09 € -1.83 2.43 2.04 0.082 0.05 mol. 1.12 L 1.57 L 5L 6.85 DO 8
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