Explain how an α particle can have a larger range in air than a β particle with the same energy in lead.
Q: A 14-gram ovarian tumor is treated using a sodium phosphate solution in which the phosphorus atoms…
A: Hey, since there are multiple questions posted, we will answer first question. If you want any…
Q: A 14-gram ovarian tumor is treated using a sodium phosphate solution in which the phosphorus atoms…
A: Hey, since there are multiple questions posted, we will answer first question. If you want any…
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A: Here, we need to derive the relationship between the half life time and the rate constant of a zero…
Q: The isotope of Nickel, 66Ni decays by β emission, has a half-life of 2.3 days. and the β particles…
A:
Q: The isotope of Nickel, 66Ni decays by β emission, has a half-life of 2.3 days. and the β particles…
A: The isotope of Nickel, 66Ni decays by β emission, has a half-life of 2.3 days. and the β particles…
Q: A 14-gram ovarian tumor is treated using a sodium phosphate solution in which the phosphorus atoms…
A: According to the company policy, only first question will be answered here. Please post the rest…
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A: (a) distance of closest approach
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Q: A 14-gram ovarian tumor is treated using a sodium phosphate solution in which the phosphorus atoms…
A: Hey, since there are multiple questions posted, we will answer first question. If you want any…
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A: (i) Number of particles absorbed is equal to the number of particles decayed
Q: A 14-gram ovarian tumor is treated using a sodium phosphate solution in which the phosphorus atoms…
A: “Hey, since there are multiple questions posted, we will answer first question. If you want any…
Q: The isotope of Nickel, 66Ni decays by β emission, has a half-life of 2.3 days. and the β particles…
A:
Q: The radium isotope 226 Ra has a hall-life of 1600 years. A sample begins with 3.50x1010 226 Ra atoms…
A: The half-life of 226Ra is T1/2 = 1600yr and the Initial amount is N0 = 3.50 x 1010
Explain how an α particle can have a larger range in air than a β particle with the same energy in lead.
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- 5 Answer the following questions: a) For a homogeneous nucleation process, sketch the dependence of the surface and bulk free energies on the radius of a spherical embryo using the equation below. kT AG, = 4rv*y -* inS V, AG > r b) Sketch the dependence of the free energy changes (AG,) on the radius of a spherical embryo when the supersaturation ratio (S) is greater than 1, equal to 1 and less than 1. AG c) Discuss the importance of supersaturation on precipitation1.a. A 14-gram ovarian tumor is treated using a sodium phosphate solution in which the phosphorus atoms are the radioative phosphorus-32 isotope with a half-life of 14.3 days and which decays via beta emision (RBE=1) with an energy of 1.71 MeV. Half of the sodium phosphate is absorbed by the tumor and deposits 9.0 J energy into it. The other half of the solution is absorbed throughout the patient's tissues, also depositing 9.0 J of energy into the 50.0 kg of body tissues. i. What is the dose ( in gray and rem) that the tumor receives? ii. What is the dose ( in milligray and rem) that the rest of the tissues receives? b. Photoelectrons from a material with a binding energy of 2.71 eV are ejected by 420-nm photons. Once ejected, how long does it take these electrons to travel 2.50cm to a detected device? c.The heating element in an electric kettle is rated as 2.0kW. If the waterin the kettle is at 1000.0 oC, what volume of water will be converted in to steam in…At t = 0 s, you have a pure sample of an unknown substance. At t = 948 s, 36.8% of the substance remains. Determine the decay constant and what t will be when 12% of the substance remains. λ = s1 t=
- 1. A person with lymphoma recieves a dose of 35 gray in the form of gamma radiation during a course of radiotherapy. Most of this dose is absorbed in 18 grams of cancerous lymphatic tissue. a. How much energy is absorbed by the cancerous tissue? b. If the treatment consist of five 15 minutes session per week over the course of 5 weeks and just one percent of the gamma Ray beam are absorbed, what is the power of the gamma ray beam? c. If the gamma ray beam consist of just 0.5 percent of the photons emitted by the gamma source each of which has an energy of 0.3MeV, what is the activity in curies of the gamma ray source?Give good explanation Asap ThanksConsider the nuclear fusion reaction 3H+ 'He > 'H + 'He. Part A Compute the binding energy of the H. Express your answer in mega-electron volts to three significant figures. B = MeV Submit Previous Answers Request Answer Part B Compute the binding energy of the He. Express your answer in mega-electron volts to three significant figures. ? B = MeV Submit Previous Answers Request Answer Part C Compute the binding energy of the H. Express your answer in mega-electron volts to three significant figures. ? B = MeV Submit Request Answer Part D Compute the binding energy of the "He. Express your answer in mega-electron volts to three significant figures. B = MeV
- 58. . Radiation treatment of prostate cancer. In many cases, BIO prostate cancer is treated by implanting 60 to 100 small seeds of radioactive material into the tumor. The energy released from the decays kills the tumor. One isotope that is used (there are others) is palladium (10°Pd), with a half-life of 17 days. If a typical grain contains 0.250 g of 10°Pd, (a) what is its initial activity rate in Bq, and (b) what is the rate 68 days later?Part A Calculate (in MeV) the total binding energy for 40 Ar. Express your answer in mega-electron volts to four significant figures. ? MeV Submit Previous Answers Request Answer X Incorrect; Try Again; 7 attempts remaining Part B Calculate (in MeV) the binding energy per nucleon for 40 Ar. Express your answer in mega-electron volts to three significant figures. Ην ΑΣφ ? Var = MeV Submit Request Answer Part C Calculate (in MeV) the total binding energy for 40K. Express your answer in mega-electron volts to four significant figures. nνα ΑΣφ ? BK = MeV Submit Previous Answers Request AnswerCompute the approximate nuclear radius of: U (ن) (d) Nit -12 I allatiun c Actinium-89