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Expert Solution Step 1 We can solve this as follows: Step 2 We have, f(x)= 8x and g(x) = x+6We need to find the composition of the given functions.So,(fog) (x)=f(g(x))=f(x+6) (since g(x)=x+6)=8(x+6) (since, f(x)=8x⇒f(x+6)=8(x+6))=8x+48 (fog)(x)=8x+48(b) (gof) (x)=g(f(x))=g(8x) (since f(x) = 8x)=8x+6 (since, g(x)=x+6⇒g(8x)=8x+6) (gof)(x)=8x+6(c)(fog) (3)=8x3+48=72(c)(gof)(3)=8x3+6=30

Expert Solution Step 1 We can solve this as follows: Step 2 We have, f(x)= 8x and g(x) = x+6We need to find the composition of the given functions.So,(fog) (x)=f(g(x))=f(x+6) (since g(x)=x+6)=8(x+6) (since, f(x)=8x⇒f(x+6)=8(x+6))=8x+48 (fog)(x)=8x+48(b) (gof) (x)=g(f(x))=g(8x) (since f(x) = 8x)=8x+6 (since, g(x)=x+6⇒g(8x)=8x+6) (gof)(x)=8x+6(c)(fog) (3)=8x3+48=72(c)(gof)(3)=8x3+6=30

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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I have the answer, but I'm a little confused as to which one it is. I answered the first question, but the second step seems to be wrong.

```markdown ## Expert Solution ### Step 1 We can solve this as follows: ### Step 2 We have, f(x) = 8x and g(x) = x + 6 We need to find the composition of the given functions. So, (f∘g)(x) = f(g(x)) = f(x + 6) (since g(x) = x + 6) = 8(x + 6) (since, f(x) = 8x ⇒ f(x + 6) = 8(x + 6)) = 8x + 48 Therefore, (f∘g)(x) = 8x + 48 (b) (g∘f)(x) = g(f(x)) = g(8x) (since f(x) = 8x) = 8x + 6 (since, g(x) = x + 6 ⇒ g(8x) = 8x + 6) (g∘f)(x) = 8x + 6 (c) (f∘g)(3) = 8×3 + 48 = 72 (c) (g∘f)(3) = 8×3 + 6 = 30 ```
Transcribed Image Text:```markdown ## Expert Solution ### Step 1 We can solve this as follows: ### Step 2 We have, f(x) = 8x and g(x) = x + 6 We need to find the composition of the given functions. So, (f∘g)(x) = f(g(x)) = f(x + 6) (since g(x) = x + 6) = 8(x + 6) (since, f(x) = 8x ⇒ f(x + 6) = 8(x + 6)) = 8x + 48 Therefore, (f∘g)(x) = 8x + 48 (b) (g∘f)(x) = g(f(x)) = g(8x) (since f(x) = 8x) = 8x + 6 (since, g(x) = x + 6 ⇒ g(8x) = 8x + 6) (g∘f)(x) = 8x + 6 (c) (f∘g)(3) = 8×3 + 48 = 72 (c) (g∘f)(3) = 8×3 + 6 = 30 ```
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