Experimental data for a reaction are plotted in the graph below. T is in units of Kelvin. The slope of the line is -2.00 x 104 K. What is the activation energy of the reaction? -6 -7 -9 -10 -11 0.0019 0.0020 0.0021 0.0022 1/T O- 2.41 x 103 kJ/mol 2.00 x 104 kJ/mol O- 166 kJ/mol O 2.41 x 10° kJ/mol O 166 kJ/mol O 1.66 x 105 kJ/mol In k

Experimental data for a reaction are plotted in the graph below. T is in units of Kelvin. The slope of the line is -2.00 x 104 K. What is the activation energy of the reaction? -6 -7 -9 -10 -11 0.0019 0.0020 0.0021 0.0022 1/T O- 2.41 x 103 kJ/mol 2.00 x 104 kJ/mol O- 166 kJ/mol O 2.41 x 10° kJ/mol O 166 kJ/mol O 1.66 x 105 kJ/mol In k

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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You have just made an aqueous solution of sodium bicarbonate. Now to determine its concentration, you need to figure out what the total volume is. We will assume that this graduated cylinder is divided into 1 mL increments. This means that we can estimate the volume to 0.1 mL to determine significant figures. Include this volume in your data table. we used a Calculate the molarity of your solution using the formula: To clean up the lab, click on the red container to the right of the bench. Data Table Total mass NaHCO3 2.0427 g Moles NaHCO3 0.02431 2.0427g/84.01g/mole L of solution Molarity of solution Calculate the Molarity of your sodium bicarbonate solution.
Sodium carbonate dissociates when it dissolves in water as follows: If the concentration of the sodium ions is 0.817 mol/L, then what is the concentration of the sodium carbonate solution? Record only your numerical answer with the correct number of significant digits. You do not need to include units as the units appear for you beside the answer box already.
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27 A chemist prepares a solution of sodium chloride (NaCl) by measuring out 0.50 g of NaCl into a 250. mL volumetric flask and filling to the mark with distilled water. Calculate the molarity of Cl anions in the chemist's solution. do Be sure your answer is rounded to 2 significant digits. 18 Ar mol x10 L Submit Assignment Continue 2022 McGraw Hill LLC. AIl Rights Reserved. Terms of Use Privacy Center Accessibility Show All IMG-6095.jpg IMG-6096.jpg IMG-6097.jpg IMG-6098.jpg IMG-6099.jpg MacBook Air DD DII F12 F11 F10 F9 80 F7 F8 F6 F5 F4 esc F2 F3 F1 & % @ # 7 8 3 4 5 6 1 2 { P E R Y Q W %24
A 9.0 mL sample of a 42.0 % (m/v) acetic acid (HC2H3O2) solution is added to water to give a final volume of 48 mL. Express your answer to two significant figures and include the appropriate units.
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A student is measuring the density of soda using a completely-filled flask of known volume. The student performing the experiment uses a sample that contains air bubbles. The student expects that this will artifically increase the calculated density of the solution. Select the answer below that is most appropriate. The student is incorrect. Air bubbles will have no effect on the calculated density of the soda. The student is incorrect. Air bubbles in the sample will cause the calculated density to decrease. The student is correct. Air bubbles in the sample will cause the calculated density to increase. The student is incorrect. Air bubbles will react with the water to form oxygen gas, which will cause the calculated density to increase. The student is incorrect. Air bubbles will react with the water to form carbon dioxide, which will cause the calculated density to increase.
You have a concentrated stock solution of 5 M NAOH and want to use it to produce a 300 mL solution of 3 M NaOH. What volume of water and stock solutions will you measure out to make this new solution? O a. 200 mL of water, 100 mL of NAOH stock O b. 100 mL of water, 200 mL of NaOH stock O c. 120 mL of water, 180 mL of NAOH stock d. 150 mL of water, 150 mL of NaOH stock
chemistry, Quicccckly please solve question 12