College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
Related questions
Question
From the slope of the graph, find the mass of the system and compare it to the expected value of 4kg using % Difference. This involves a derivation – show how you get the mass from the slope.

Transcribed Image Text:Experimental Acceleration vs Accelerating Force
8
y = 1.0107x.esi
7
1
1
2
3
4
5
6
7
Accelerating Force
co
6.
st
2.
Experimental Acceleration

Transcribed Image Text:Eq 1.
Eq 2.
EF
Eq 3.
Σε
F = Whanging
= m19
m19
at?
1
аехресted
Ay =
M
M
(1kg)(9.8)/1kg+3kg =
2.45 m/s^2
(2kg)(9.8)/2kg+2kg =
4.90 m/s^2
1kg(9.8) = 9.8 N
2(2.02m)/(1.28s)^2
= 2.47 m/s^2
2(2.02m)/(0.91s)^2
= 4.89 m/s^2
Run 1
Run 2
2kg(9.8) = 19.6 N
%3!
Run 3
3kg(9.8) = 29.4 N
(3kg)(9.8)/3kg+1kg =
7.35 m/s^2
2(2.02m)/(0.74s)^2
= 7.38 m/s^2
%3D
%3!
Expert Solution

Step 1
We are given the graph of acceleration vs accelerating force and the graph is a straight line as follows :
Determine:
the mass of the system by using slope of the graph
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