Can someone please help me solve these questions and all sub questions using MiniTab. Please and Thank you!!! **The effective life of insulating fluids at an accelerated load of 35 kV is being studied. Test data have been obtained for four types of fluids. The results from a completely randomized experiment were as follows: Please do your analysis in Minitab and Excel, upload your Minitab and Excel files, and answer the following questions.**| Fluid Type | Life (in h) at 35 kV Load ||------------|---------------------------|| 1 | 17.6, 18.9, 16.3, 17.4, 20.1, 21.6 || 2 | 16.9, 15.3, 18.6, 17.1, 19.5, 20.3 || 3 | 21.4, 23.6, 19.4, 18.5, 20.5, 22.3 || 4 | 19.3, 21.1, 16.9, 17.5, 18.3, 19.8 |**Questions:**a) What is the number of replicates in these experiments?b) What is the response variable (output)?c) What is the factor?d) How many factors do we have for this problem?e) How many levels are considered for the factor?f) What test should be used to know whether all 4 different fluid types have the same effect on mean of effective life for insulating fluids?g) Using the Excel Analysis and Minitab ANOVA test, do all different fluid types have the same effect on the effective life of insulating fluids? **Explanation:**The table shows the lifespan of different insulating fluid types under a 35 kV load. Each fluid type has multiple observations. The goal is to determine if all fluid types affect the lifespan similarly through statistical methods like ANOVA. ### Hypothesis Testing and Analysis**h) What is the null hypothesis (H0) for this problem?**The null hypothesis (H0) typically states that there is no effect or no difference. It is the hypothesis that the researcher seeks to test against.**i) What is the alternative hypothesis (H1 or HA) for this problem?**The alternative hypothesis (H1 or HA) proposes that there is an effect or a difference. It is what the researcher wants to prove.**j) After running the proper test, what is the P-value for this problem?**The P-value indicates the probability of observing the test results under the null hypothesis. A low P-value suggests that the null hypothesis may not be true.**k) What value did you choose for the error type I (significance level) α for this problem?**The significance level (α) is the probability of rejecting the null hypothesis when it is true. Common values are 0.05, 0.01, and 0.10.**l) What is confidence level?**The confidence level represents the degree of certainty in the interval estimate of a parameter. It is the complement of the significance level (e.g., a 95% confidence level corresponds to an α of 0.05).**m) After solving the question, what value did you get for the F test statistic?**The F test statistic is used to compare variances and test for significant differences between group means in analysis of variance (ANOVA).**n) What value did you get for sum of square treatment (source of variation between groups due to factor)?**The sum of square treatment measures the variation between group means. It is used in ANOVA to assess the effect of different levels of a factor.**o) What value did you get for sum of square error (source of variation within group due to error)?**The sum of square error measures the variation within groups. It is the residual variation not explained by the treatment.**p) Using Minitab, plot the residuals versus the predicted response. Construct a normal probability plot of the residuals. What information is conveyed by these plots?**Residual plots help diagnose the fit of a model by showing the difference between observed and predicted values. A normal probability plot checks if residuals follow a normal distribution, indicating the assumptions of the statistical test are met.

“Since you have posted a question with multiple sub-parts, we will solve first three subparts for you. To get remaining sub-part solved please repost the complete question and mention the sub-parts to be solved.”.a) The replicates are the repetition of the experiment conducted under a particular treatment. So for the given study, the number of replicates is given by the sample size obtained under each treatment which is six. Hence the number of replicates is 6.b) In the given experiment, the replications are made to observe the lifespan of the insulating fluid which is considered as the response to the type of fluid being used which means the response variable, in this case, is the life of the insulating fluid.(c) A factor is a variable that is used in an experiment to determine if it influences the response variable or how it influences the response variable. In the given case, the factor variable of the experiment is the type of fluid.