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Experiment: Preparation of Soap Volume of Coconut Oil: 10 mL Density of Coconut oil: 0.903 g/mL Volume of Sodium Hydroxide (3M): 15 mL Sodium Chloride solution saturated: 50 mL Molecular Weight Coconut Oil: 554.8 g/mol Mass of soap collected: 22.852 grams Molecular weight of soap: 584.3 g/mol

Experiment: Preparation of Soap Volume of Coconut Oil: 10 mL Density of Coconut oil: 0.903 g/mL Volume of Sodium Hydroxide (3M): 15 mL Sodium Chloride solution saturated: 50 mL Molecular Weight Coconut Oil: 554.8 g/mol Mass of soap collected: 22.852 grams Molecular weight of soap: 584.3 g/mol

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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please help find limiting given the data 

Experiment: Preparation of Soap Volume of Coconut Oil: 10 mL Density of Coconut oil: 0.903 g/mL Volume of Sodium Hydroxide (3M): 15 mL Sodium Chloride solution saturated: 50 mL Molecular Weight Coconut Oil: 554.8 g/mol Mass of soap collected: 22.852 grams Molecular weight of soap: 584.3 g/mol
Transcribed Image Text:Experiment: Preparation of Soap Volume of Coconut Oil: 10 mL Density of Coconut oil: 0.903 g/mL Volume of Sodium Hydroxide (3M): 15 mL Sodium Chloride solution saturated: 50 mL Molecular Weight Coconut Oil: 554.8 g/mol Mass of soap collected: 22.852 grams Molecular weight of soap: 584.3 g/mol
Determine the limiting reactant. Show your work example: (5 grams of A)/(10 g/mol of A) = 0.5 moles of A (0.5 moles of A) (2 moles of B/1 moles of A)*(5 grams/mol of B)= 50 grams of B
Transcribed Image Text:Determine the limiting reactant. Show your work example: (5 grams of A)/(10 g/mol of A) = 0.5 moles of A (0.5 moles of A) (2 moles of B/1 moles of A)*(5 grams/mol of B)= 50 grams of B
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