Experiment :LEE’S DISC I want the Analysis for this experiment

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Experiment :LEE’S DISC

I want the Analysis for this experiment 

Time (min)
2
4
6
8 10 12 14 16 18 20 22 24 26 28 30
Temperature
59 58 57 56 56 56 55 54 53 52 51 50 49 48 47 46
(°C)
Temperature vs Time graph
70
60
E 50
40
30
10
10
15
20
25
30
35
Time (min)
calculations:
de
46-56
-10
Slope=
dt
= -0.5
30-10
20
de
From the graph,
slope = Rate of cooling = -0.5
%3D
dt
The Thermal Conductivity constant may be calculated as
de
m x X-
xd
803g x0.380 j/g°c x 0.5 c/s x 1.70mm
9555.22mm2 x( 73°c-55°c)
k =
1.508 x 10-3
A(T,-T,)
Where c= Specific heat capacity of brass = 0.380 j/gs
%3!
Temperature (°C)
Transcribed Image Text:Time (min) 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 Temperature 59 58 57 56 56 56 55 54 53 52 51 50 49 48 47 46 (°C) Temperature vs Time graph 70 60 E 50 40 30 10 10 15 20 25 30 35 Time (min) calculations: de 46-56 -10 Slope= dt = -0.5 30-10 20 de From the graph, slope = Rate of cooling = -0.5 %3D dt The Thermal Conductivity constant may be calculated as de m x X- xd 803g x0.380 j/g°c x 0.5 c/s x 1.70mm 9555.22mm2 x( 73°c-55°c) k = 1.508 x 10-3 A(T,-T,) Where c= Specific heat capacity of brass = 0.380 j/gs %3! Temperature (°C)
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