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Expedia would like to test the hypothesis that the proportion of Southwest Airline flights that arrive on-tim is less than 0.90. A random sample of 140 United Airline flights found that 119 arrived on-time. Expedia would lik to set a = 0.05. For this hypothesis test, the critical valu would be and the test statistic would be O 20.05 1.64; zp = -1.66 O z0.05 = 1.64; zp = –1.97 20.025 = 1.96; zp = -1.66 O z0.025 = 1.96; z, = -1.97

Expedia would like to test the hypothesis that the proportion of Southwest Airline flights that arrive on-tim is less than 0.90. A random sample of 140 United Airline flights found that 119 arrived on-time. Expedia would lik to set a = 0.05. For this hypothesis test, the critical valu would be and the test statistic would be O 20.05 1.64; zp = -1.66 O z0.05 = 1.64; zp = –1.97 20.025 = 1.96; zp = -1.66 O z0.025 = 1.96; z, = -1.97

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter4: Equations Of Linear Functions
Section4.6: Regression And Median-fit Lines
Problem 4GP
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Expedia would like to test the hypothesis that the proportion of Southwest Airline flights that arrive on-time is less than 0.90. A random sample of 140 United Airline flights found that 119 arrived on-time. Expedia would like to set a = 0.05. For this hypothesis test, the critical value would be and the test statistic would be O z0.05 1.64; zp = -1.66 O Z0.05 1.64; zp = -1.97 O 20.025 1.96; zp = -1.66 = O 20.025 = 1.96; zp = –1.97
Transcribed Image Text:Expedia would like to test the hypothesis that the proportion of Southwest Airline flights that arrive on-time is less than 0.90. A random sample of 140 United Airline flights found that 119 arrived on-time. Expedia would like to set a = 0.05. For this hypothesis test, the critical value would be and the test statistic would be O z0.05 1.64; zp = -1.66 O Z0.05 1.64; zp = -1.97 O 20.025 1.96; zp = -1.66 = O 20.025 = 1.96; zp = –1.97
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