Expand the quotients in Exercises 1–8 by partial fractions. 5x 13 5х — 7 1. (x 2. 3)(х — 2) Зх + 2 x + 4 2x + 2 3. 4. (x + 1)² 2х + 1 5. z²(z – 1) 6. 6z 12 + 8 tA + 9 8. pA + 9t² 12 – 5t + 6 7.

Q: x-1 Decompose as a sum of partial fraction 4x –1 Ax + B а. 4x -1 | A В b. 1 1 x+ 2 A В с. 1 2| x 2 1…

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Q: b) –5x + 3 > 8 6 –5 –4 –3 –2 –1 0 i 2 3 -3 - 2 4 5 6 |

A: Given, -5x+3≥8 Aim: Graph inequality

Q: 4 0 -8 -8 -21 -13 16 -6 -2 4 4 m What is the quotient?

A: We have to choose the correct answer from the given option according to the given condition

Q: 4-x lim,.

A: The given limit is limx→∞4-xx

Q: -12и-13 6. (2и+1) (иl)

A: Topic = Algebra

Q: (-4a b)(-3a'b) 6a'b? 9. +16a?

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Q: In Exercises 83–92, factor by introducing an appropriate substitution. 83. 2r* – x? – 3 84. 5x4 +…

A: To factor the polynomial: 2x4-x2-3 Solution: 2x4-x2-3Substituting x2=t in above expression we…

Q: In Exercises 34–37, solve each polynomial equation. 34. 3x? = 5x + 2 35. (5x + 4)(x – 1) = 2 36.…

A: 34. Given polynomial function is: 3x2=5x+2 Rearranging the terms we get, 3x2-5x-2=0 Solving we get,…

Q: 3.9b + a3 + 27 - 3a2 + 5a3 - 2a2 + 2.1b + 7

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Q: 2. S 2z+8 dz (z+7)a

A: A detailed solution is given below

Q: 16 If X-B (4, p) and P (X=0)=- then P (X=4) 81

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Q: x² –1 4. x2 -4 (-2, – 1], [1,2)

A: Given :

Q: 3a + 46° – 5 = 3 (6) +4(2) – 5 ? ||

A: Solution: The objective is to calculate the value

Q: Express each fraction in its simplest form. y3 + 2y (a) 2у — у2 5x² + 5 (b) 10х — 10 5.

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Q: 3x2 - x - 2

A: Given function is 3x2-x-2 We can write 3x2-x-2=3x2-3x+2x-23x2-x-2=3x(x-1)+2(x-1)3x2-x-2=(3x+2)(x-1)

Q: -31 If A = [²2² =2²] B = [²34 21 6 -2. Find 2A - (B + A)

A: given

Q: 2 1. x3/8

A: As per our guidelines we are suppose to solve only first question if the multiple questions are…

Q: 10) (n + 4)

A: (a+b)2 = a2 + b2 + 2ab (n+4)2 = n2 + 16 + 2 × n × 4             = n2 + 8n + 16

Q: 2 S²3 (x²-3x+18) 9x-X³

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Q: 6-73 21. lim t→+ 7t3+3

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Q: S(in 6x) dx x (In 6x)2 - 2x (In 6x) +c x (In 6x)2 - x (In 6x) + x + C <(In 6x)2 - 2x х (in 6x)2 + 2x…

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Q: 1. 2x - 1 2x - 3 X x + 1 2x + 1 2x² - x - 3 = 0

A: Given equation:- 2x-12x-3-xx+1-2x+12x2-x-3=0

Q: 6х3 + х2— 5х —7 –dx. Use Зx2 —х — 2

A:

Q: Example 6 If ð = (3, 2), b =(5, –1), ĉ = (-4, 2) find (a) 2a + b – 3c (b) 3a + 26 – 7.

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Q: 4. (4x + )(4x - ) +

A:

Q: 3. S 8x3 37x2 + 80x-32 4x4 — 16х3+ 32х2 dx (By Partial Fractions)

A: The given integral is: ∫8x3-37x2+80x-324x4-16x3+32x2dx

Q: (2х — Зу)(4x? + 6ху + 9у?)

A:

Q: (9x – 10x – 4x2 + 2x) – (4x° – 9x* + 2x² – 6) O 5x* + 9x* – 10x³ – óx? + 2x + 6 O 5x° – 9x* – 10x³ -…

A: The given expression is: (9x5-10x3-4x2+2x)-(4x5-9x4+2x2-6)

Q: 6 - 16 =20 2 #(0) = – 2, y(0) =

A: Given query is to solve the given initial value problemx'y'=61-292xyx0=-2y0=-16

Q: A x² B --x-In Ix+11+ C x² 2 -x+ In lx+11+ C 5x²=² dx x+1 C x² D x² +x-In Ix+11+ C +x+ In lx+11+ C

A: The given integral,              ∫x2-2x+1dx