Exercise. Let C be a curve drawn by: p(t) = (2 cos(t), –-2 sin(t)) Find the length of the curve drawn by p as t runs from 0 to T: length = | ?
Exercise. Let C be a curve drawn by: p(t) = (2 cos(t), –-2 sin(t)) Find the length of the curve drawn by p as t runs from 0 to T: length = | ?
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Can u help me answer all three question please? Thank you.
![Exercise. Let C be a curve drawn by:
p(t) = (2 cos(t), –-2 sin(t))
Find the length of the curve drawn by p as t runs from 0 to T:
length =
2.
Exercise. The starting position of a particle is given by
p(0) = (5, –2)
Suppose the initial velocity is given by v(0) = (1,2) and the acceleration is given by a(t) = (2,3). Find:
• The velocity function: v(t) =
• The speed function: s(t) =
• The position function: p(t)
=
3
Exercise. The position vector for a particle is described by the vector-valued function:
sin(at)
for t > 0. Find (positive) a so the curve uses arc length as a parameter.
a =
4
6](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2bd56bd9-20a1-4883-92af-f78f88215242%2F14082ff0-b20e-4500-be25-603052874867%2Fxhbbsva_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Exercise. Let C be a curve drawn by:
p(t) = (2 cos(t), –-2 sin(t))
Find the length of the curve drawn by p as t runs from 0 to T:
length =
2.
Exercise. The starting position of a particle is given by
p(0) = (5, –2)
Suppose the initial velocity is given by v(0) = (1,2) and the acceleration is given by a(t) = (2,3). Find:
• The velocity function: v(t) =
• The speed function: s(t) =
• The position function: p(t)
=
3
Exercise. The position vector for a particle is described by the vector-valued function:
sin(at)
for t > 0. Find (positive) a so the curve uses arc length as a parameter.
a =
4
6
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