Exercise To Try 13 Find using implicit differentiation, of 2x³ – xy³ = 3. NOTE: You will use product rule here.

Q: first derivative y= 4in Gty) is dy 4.

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Q: Q1; Find Taylor series of the function f(x) = Vx at a = 36. ( piul) %3D

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Q: y +x = xln y

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Q: 6x Find 4 for the curve given by x²y+xy%=

A: We have to find dydx for the given curve x2y+xy2=6x.

Q: 2х-у x3 x+3

A: The given function is x3=2x-yx+3y

Q: Please use implicit differentiation so that I can understand the concept better.

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Q: it differentiation

A: Assume that y is a function of x , or y=f(x)y2=f(x)2   ddx(y2)=ddxf(x)2

Q: 1 f (x) = x4 – Vx³ + x$

A: The function is given by fx = x4-x3+x18 To evaluate: The derivative of the function.

Q: A. Find y' if 3. Jx2 + y² = 2xy %3D

A: Given: x2+y2=2xy For finding value of y', we differentiate given expression with respect to x

Q: x² + y² = a final should be answer -IN find d²y dx² 19 ²2 x ²2/2/2 主

A: Since, you have posted multiple questions. As per guidelines we are supposed to answer only first…

Q: - Find the following derivatives. d. In(x2 + 1) dx

A: Given query is to find the derivative of the expression.

Q: Use implicit differentiation to find az/ax and ôz/ðy e7z = xyz %3D yz 7z az %3D e – xy - az %3D ay…

A: Given function is Differentiating partially with respect to x, we get