Exercise 8.2. Let a e Sym (10) be given by α= = (1357) (126) (379) (0543) Write a as a product of disjoint cycles.
Exercise 8.2. Let a e Sym (10) be given by α= = (1357) (126) (379) (0543) Write a as a product of disjoint cycles.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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[sets and number] please explain it using simple words and step by step, thanks :)

Transcribed Image Text:Exercise 8.2. Let a e Sym(10) be given by
a = (1357) (126) (379)(0543)
Write a as a product of disjoint cycles.
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Follow-up Questions
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Follow-up Question
soyry, I think u might get wrong. Because u start from left to right in this part, u can check it on my image. Actually, the composition of transpositions should start from right to left.

Transcribed Image Text:→
= (1357) (126) (379) (0543) @ Sym (10).
8
2
S
L
Step 2: Write as product of disjoint cycles
We
have
Now, write all cycle as permutation, weget
2 =
0
I 2
อ 1
0 1 2 3 4 5 6 7 8 9
03 25 4 7 6 1
89
(st
x = (13
(135)) (136) (37-19) (0 543) e Syndin).
x = (
3 4 5 6 7 8 9
7 4 5 6 9 83
Now multiply all permutations,
2 3
4
439
0 2 6 3 4
1
512
DO
12= poros=4 = $(8 (814)))
So we need to start from
4
So 07
1-2
2→6
31
2 3 4 5 6 7 8 9
1789
2 3 4 5 6 7 8 97
0 3 4678
get
we
8
128
(9)
rather than 1.
Solution
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