Exercise 7.3 Two independent experiments are run in which two different types of paint are computed. Eighteen specimens are painted using type A, and drying time (in hours) is recorded each. The same is done with type B. The population standard deviations are both known to be 1.0. Assume that the mean drying time is equal for the two types of paint, find P(XA – X3 > 1.0), where Xa and Xg are average drying times for samples of size na = DR = 18.

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Chapter1: Combinatorial Analysis
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exercise 7.3

Exercise 7.3 Two independent experiments are run in which two different types of
paint are computed. Eighteen specimens are painted using type A, and drying time
(in hours) is recorded each. The same is done with type B. The population
standard deviations are both known to be 1.0. Assume that the mean drying time
is equal for the two types of paint, find P(XA – X > 1.0), where Xa and Xg are
average drying times for samples of size na = nB = 18.
Transcribed Image Text:Exercise 7.3 Two independent experiments are run in which two different types of paint are computed. Eighteen specimens are painted using type A, and drying time (in hours) is recorded each. The same is done with type B. The population standard deviations are both known to be 1.0. Assume that the mean drying time is equal for the two types of paint, find P(XA – X > 1.0), where Xa and Xg are average drying times for samples of size na = nB = 18.
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