EXERCISE 6 (PSAT – 20151028 Section 4, Q9) (Calculator permitted) f (x) = x2 + 4(x – 3) Which of the following is an equivalent form of the expression above that displays the zeros of the function as constants or coefficients in the expression? A) f(x) = x² + 4x – 12 B) f(x) = (x – 6)(x +2) C) f(x) = (x + 6)(x – 2) D) f(x) = (x +2)² – 16 -
EXERCISE 6 (PSAT – 20151028 Section 4, Q9) (Calculator permitted) f (x) = x2 + 4(x – 3) Which of the following is an equivalent form of the expression above that displays the zeros of the function as constants or coefficients in the expression? A) f(x) = x² + 4x – 12 B) f(x) = (x – 6)(x +2) C) f(x) = (x + 6)(x – 2) D) f(x) = (x +2)² – 16 -
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![EXERCISE 6
(PSAT – 20151028 Section 4, Q9) (Calculator permitted)
f(x)
= x + 4(x – 3)
Which of the following is an equivalent form of the expression above that displays the zeros of the function as
constants or coefficients in the expression?
A) f(x) = x² + 4x – 12
B) f(x) = (x – 6)(x + 2)
C) f(x) = (x + 6)(x – 2)
D) f(x) = (x +2)² – 16](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffe64000f-c2f6-4ca3-b29e-d111590b6f69%2F62329981-1984-4877-998f-9aa4869a7d4b%2Fn9rtrcj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:EXERCISE 6
(PSAT – 20151028 Section 4, Q9) (Calculator permitted)
f(x)
= x + 4(x – 3)
Which of the following is an equivalent form of the expression above that displays the zeros of the function as
constants or coefficients in the expression?
A) f(x) = x² + 4x – 12
B) f(x) = (x – 6)(x + 2)
C) f(x) = (x + 6)(x – 2)
D) f(x) = (x +2)² – 16
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