Exercise 6: Consider the function: f(x) = arctan Show that f'(r) = 1/(1+ x²). Show there does not exist c ER such that arctan(x) + c = f (x). Why does this not contradict the second fundamental theorem of calculus?
Exercise 6: Consider the function: f(x) = arctan Show that f'(r) = 1/(1+ x²). Show there does not exist c ER such that arctan(x) + c = f (x). Why does this not contradict the second fundamental theorem of calculus?
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![Exercise 6: Consider the function:
f(x) = arctan
Show that f'(r) = 1/(1+ x²). Show there does not exist c ER such that arctan(x) + c = f (x). Why
does this not contradict the second fundamental theorem of calculus?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd278ed62-b725-4a86-a1fe-982d6fd45a66%2Fe1d37b3a-6afb-4499-b25e-56501f8d2294%2F7vl91nn.png&w=3840&q=75)
Transcribed Image Text:Exercise 6: Consider the function:
f(x) = arctan
Show that f'(r) = 1/(1+ x²). Show there does not exist c ER such that arctan(x) + c = f (x). Why
does this not contradict the second fundamental theorem of calculus?
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